Find the mean, variance, and standard deviation for each of the values of n a are met. Round your answers to three decimal places as needed. Part: 0 / 4 Part 1 of 4 (a) n=80, p=0.71 56.8 = 16.472 1.842 Mean: μ 2 Variance: ² = Standard deviation: o = Part: 1 / 4 Part 2 of 4 (b) n = 22, p=0.51 Mean: μ = Variance: ² = Standard deviation: 0 = Next Part X

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### Example of Finding Mean, Variance, and Standard Deviation

Find the mean, variance, and standard deviation for each of the values of \( n \) and \( p \) listed below. Round your answers to three decimal places as needed.

#### Part 0 of 4
(Instruction part, no numerical input required here)

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#### **Part 1 of 4**

For \( n = 80 \) and \( p = 0.71 \):
- **Mean (\(\mu\))**: \( \mu = 56.8 \)
- **Variance (\(\sigma^2\))**: \( \sigma^2 = 16.472 \)
- **Standard Deviation (\(\sigma\))**: \( \sigma = 1.842 \)

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#### **Part 2 of 4**

For \( n = 22 \) and \( p = 0.51 \):
- **Mean (\(\mu\))**: (to be filled in by the user)
- **Variance (\(\sigma^2\))**: (to be filled in by the user)
- **Standard Deviation (\(\sigma\))**: (to be filled in by the user)

---

[Next Part Button]

---

Explanation:
- **Mean (\(\mu\))**: This is the expected value of the distribution. It is calculated as \( \mu = n \cdot p \).
- **Variance (\(\sigma^2\))**: This measures the spread of the distribution. It is calculated as \( \sigma^2 = n \cdot p \cdot (1-p) \).
- **Standard Deviation (\(\sigma\))**: This is the square root of the variance, providing a measure of how spread out the values in the distribution are. It is calculated as \( \sigma = \sqrt{n \cdot p \cdot (1-p)} \).

Graphical representation: 
This image segment does not include any graphs or diagrams. All values given and required calculations are presented in a tabular format for easy understanding and completion.

[Note: Detailed calculations not shown here must be computed by students as part of the learning exercise.]
Transcribed Image Text:### Example of Finding Mean, Variance, and Standard Deviation Find the mean, variance, and standard deviation for each of the values of \( n \) and \( p \) listed below. Round your answers to three decimal places as needed. #### Part 0 of 4 (Instruction part, no numerical input required here) --- #### **Part 1 of 4** For \( n = 80 \) and \( p = 0.71 \): - **Mean (\(\mu\))**: \( \mu = 56.8 \) - **Variance (\(\sigma^2\))**: \( \sigma^2 = 16.472 \) - **Standard Deviation (\(\sigma\))**: \( \sigma = 1.842 \) --- #### **Part 2 of 4** For \( n = 22 \) and \( p = 0.51 \): - **Mean (\(\mu\))**: (to be filled in by the user) - **Variance (\(\sigma^2\))**: (to be filled in by the user) - **Standard Deviation (\(\sigma\))**: (to be filled in by the user) --- [Next Part Button] --- Explanation: - **Mean (\(\mu\))**: This is the expected value of the distribution. It is calculated as \( \mu = n \cdot p \). - **Variance (\(\sigma^2\))**: This measures the spread of the distribution. It is calculated as \( \sigma^2 = n \cdot p \cdot (1-p) \). - **Standard Deviation (\(\sigma\))**: This is the square root of the variance, providing a measure of how spread out the values in the distribution are. It is calculated as \( \sigma = \sqrt{n \cdot p \cdot (1-p)} \). Graphical representation: This image segment does not include any graphs or diagrams. All values given and required calculations are presented in a tabular format for easy understanding and completion. [Note: Detailed calculations not shown here must be computed by students as part of the learning exercise.]
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