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- A random sample of size 29 is selected from a normal population with mean = and variance = 8. Determine the probability that s? (the sample variance) is between 11.81 and 14.57. 12Computer hard drives must rotate in a balanced way and away from level is called pitch.Samples are taken regularly from production and each disk in the sample is placed in test equipment that results in a pitch measurement. From various samples it is concluded that the population is normal. The variance = image 1 when the process is in control. A sample of 10 is collected each week. The process will be declared out of control if the sample variance exceeds 0.122 What is the probability that it is declared out of control even when variance = image 1?random sample of 10 subjects have weights with a standard deviation of 10.9919 kg. What is the variance of their weights? Be sure to include the appropriate units with the result.
- A random sample of 10 subjects have weights with a standard deviation of 10.9654 kg what is the variance of their weights be sure to include the appropriate units with the resultThe mean and variance of the getting two times of number 4 in 10 fair die tosses with Bernoulli trails is Mean = 10*4 variance = 10*4*(10-4) %3D Mean =(4)*(1/10) variance = 10* (1/4) *(1/ (10-4)) %3D None of thempls show solutions thank u
- A proton emitter produces proton beams with changing kinetic energy that is uniformly distributed between three and eight joules. Suppose that it is possible to adjust the upper limit of the kinetic energy (currently set to eight joules). • What is the mean kinetic energy? What is the variance of the kinetic energy? What is the probability that a proton beam has a kinetic energy of exactly 3.5 joules? a. E(X) = 5.5, V(X) = 2.0833, probability is zero (0) because X has a continuous distribution O b. E(X) = 5, V(X) = 1.33, probability is zero (0) because X has a uniform distribution O c. NONE O d. E(X) = 5.5, V(X) = 2.0833, probability is zero (0) because X has a uniform distributionIf population variance o? = 49 and sample 196 then, standard error S.E.(T) will size n = beWhen compared with the Pearson correlation, the Spearman correlation coefficient is: Less statistical power when the sample size is <50, True or false?