Defective alternator and corroded or loose battery charges are a few of the main causes of battery degradation. A company producing automobile batteries is developing a prototype on their next product and that they claim their batteries will last on average, 3 years with a variance of 1 year. A random sample of 5 prototype batteries were taken and in the course of the company’s product development, have measured their lifetimes as 1.9, 2.4, 3.0, 3.5, and 4.2 years.
Defective alternator and corroded or loose battery charges are a few of the main causes of battery degradation. A company producing automobile batteries is developing a prototype on their next product and that they claim their batteries will last on average, 3 years with a variance of 1 year. A random sample of 5 prototype batteries were taken and in the course of the company’s product development, have measured their lifetimes as 1.9, 2.4, 3.0, 3.5, and 4.2 years.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:CI on Variance
Defective alternator and corroded or loose battery charges are a few of the main causes of battery
degradation. A company producing automobile batteries is developing a prototype on their next product
and that they claim their batteries will last on average, 3 years with a variance of 1 year. A random sample
of 5 prototype batteries were taken and in the course of the company’s product development, have
measured their lifetimes as 1.9, 2.4, 3.0, 3.5, and 4.2 years.
Construct a 95% confidence interval for o and decide if the company's claim that o? = 1 is valid. Assume
the population of battery lives to be approximately normally distributed.
O a. 0.34 < o2 < 4.59. Because 95% confidence interval for o? is (0.34, 4.59), and the s2 = 0.815
is in that interval, we can conclude that the company's claim is valid
O b. 0.29 < o² < 6.74. 95% confidence interval for o² is (0.29, 6.74)
O c. 0.539 < o < 2.596. Because 95% confidence interval for o is (0.539, 2.596), and 1 is in that
interval, we can conclude that the company's claim that o = 1 is valid
O d. 0.29 < o? < 6.74. Because 95% confidence interval for o? is (0.29, 6.74), and 1 is in that
interval, we can conclude that the company's claim that o? = 1 is valid
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