Question 9: Use Cramer's rule to solve: 6x1 + 2x2x3 = 0 3x1 + 3x2 + 2x3 = -1 4x1- x₂ + 3x3 = 1

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Q: 16. A solution of the initial value problem y'+8y=1+e". y(0)=0 is (1) = 8 + 1/₂" - 5/e* TI a. b.…

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