Question 9 The endpoints of a diameter of a circle are P(1, 4) and Q(4, 7). Find the equation of the circle. O a. (* - 5) + (y – 5.5) = 2.25 O b. (x + 2.5) + y + 5.5)² = 4.5 Oc(* - 2)2 + (v – 5)? = 4.5 Od. (x - 5) + y? = 26 O e. (x - 2.5)2 + (y - 5.5) = 4.5 %3D
Question 9 The endpoints of a diameter of a circle are P(1, 4) and Q(4, 7). Find the equation of the circle. O a. (* - 5) + (y – 5.5) = 2.25 O b. (x + 2.5) + y + 5.5)² = 4.5 Oc(* - 2)2 + (v – 5)? = 4.5 Od. (x - 5) + y? = 26 O e. (x - 2.5)2 + (y - 5.5) = 4.5 %3D
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter10: Analytic Geometry
Section10.2: Graphs Of Linear Equations And Slope
Problem 45E
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![Moving to the next question prevents changes to this answer.
Ruestion 9
The endpoints of a diameter of a circle are P(1, 4) and Q(4, 7). Find the equation of the circle.
O a. (* - 5) + (y – 5.5) = 2.25
O b. (* + 2.5)² + v + 5.5)² = 4.5
Oc& - 2) + (y – 5)² = 4.5
O d. (* - 5) + y2 = 26
Oe.(x - 2.5)2 + ( – 5.5) = 4.5
||
%3D
A Moving to the next question prevents changes to this answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffa329a63-54f7-42d8-85e8-e378afa85201%2F1c64b21d-5a90-4f4f-9724-649716ddd241%2Fzlk8bpn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Moving to the next question prevents changes to this answer.
Ruestion 9
The endpoints of a diameter of a circle are P(1, 4) and Q(4, 7). Find the equation of the circle.
O a. (* - 5) + (y – 5.5) = 2.25
O b. (* + 2.5)² + v + 5.5)² = 4.5
Oc& - 2) + (y – 5)² = 4.5
O d. (* - 5) + y2 = 26
Oe.(x - 2.5)2 + ( – 5.5) = 4.5
||
%3D
A Moving to the next question prevents changes to this answer.
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