ViMmIn the diagram above, a block of mass M is initially at rest on a horizontal surface at the base of an inclined plane. The surface anblock, and they move together to the right with speed vf.The block and projectile smoothly transition onto the inclined plane. Which of the following is a correct expression for the maximuA2gUf2gMu2mg2g2gE. Question 9V¡hMmIn the diagram above, a block of mass M is initially at rest on a horizontal surface at the base of an inclined plane. The surface and plane have negligible friction. The block is struck by a projectile of mass m traveling with a horizontal velocity v. The projectile becomes embedded in theblock, and they move together to the right with speed uf.The block and projectile smoothly transition onto the inclined plane. Which of the following is a correct expression for the maximum height that the block moves up the inclined plane in terms of vf ?A2gMeC2mgD.

Answer: As per the given data, The mass of the block is at rest initially on the horizontal surface on the base of an inclined plane. whenever a projectile is made with a certain angle and it's embedded in the block and they move together right with a speed is given as vf.Explanation: Whenever anybody travels or projects at angle incline with the surface and moves together with a certain velocity then the block and projectile smoothly travel into the inclined plane such that it travels maximum height h as given as: h=vf22gwhere,vf=speed g=acceleration due to gravityThus, As per the above explanation: The Maximum height travelled by a block in an inclined plane is given as: h2=vf2g Hence, Option A is correct.

Answered: Question 9 A Vi h M m In the diagram…