O 350,000 and 600,000 hoursDou and osuj nodQuestion 8Assume the mean useful life of a Caterpillar motor is 500,000 hours and is normally distributewith a standard deviation of ± 50,000 hours. Calculate the percent of Caterpillar motors thatlast 605,000 hours or more.O 16%Ⓒ 34%0.15%- 25%ED4TONo new data to save Last checked at 4:18pm SubrYBIN31

Given: Mean μ = 500,000 Standard deviation σ = 50,000 X = 605,000 Formula Used: Z-score = X-μσ

Answered: Question 8 Assume the mean useful life…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question 10 く Suppose that we are studying the amount of time customers wait in line at the checkout at the Gap and Old Navy. The avérage wait time at both stores is five minutes. At the Gap, the standard deviation for the wait time is 2 minutes; at Old Navy the standard deviation for the wait time is 5 minutes. Because Old Navy has a higher standard deviation, we know that there is Select an answer v in the wait times at Old Navy. Overall, wait times at Old Navy are Select an answer v from the average; wait times at the Gap are Select an answer v near the average.
Question 5 A particular fruit's weights are normally distributed, with a mean of 479 grams and a standard deviation of 17 grams. If you pick 24 fruits at random, then 12% of the time, their mean weight will be greater than how many grams? Give your answer to the nearest gram.
Question 36 An honor society on campus only accepts the top 13% of students (according to GPA). If the GPAS of all students on campus are known to be a normally distributed with a mean of 2.99 and a standard deviation of 0.45, determine the minimum GPA a student must achieve in order to be admitted to the honor society. Round the solution to two decimal places, if necessary. A minimum GPA of is required for admission to the honor society.
Question 4
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QUESTION 6 The amount of time for an oil change at a particular service station is normally distributed with a mean of 23.2 minutes and a standard deviation of 3.8 minutes. Find each value below. Round all answers to two decimal places. Type the number only; do not include units. What length of time separates the top 3% of oil change durations at this station? minutes What length of time separates the bottom 15% of oil change durations at this station? minutes What are the two lengths of time that have, between them, the middle 90% of oil change durations at this station? (You will find two values, a lower endpoint and an upper endpoint. Between these values is the middle 90% of observations for this distribution.) Lower endpoint: Upper endpoint: minutes minutes
QUESTION 13 Find the standard deviation for the given data. Round your answer to one more decimal place than the original data. 10, 9, 20, 12, 19, 11, 14, 13, 20 1.8 4.4 4.1 4.7 O00
QUESTION 4 Eight independent measurements were made along a line and the standard deviation was found to be 10.55. Determine the error at 99.7% probability. State you answer to two decimal places.
Question 7 of 9 < -/1 E Current Attempt in Progress The mean consumption of water per household in a city was 1231 cubic feet per month. Due to a water shortage because of a drought, the city council campaigned for water use conservation by households. A few months after the campaign was started, the mean consumption of water for a sample of 92 households was found to be 1151 cubic feet per month. The population standard deviation is given to be 248 cubic feet. a. Find the p-value for the hypothesis test that the mean consumption of water per household has decreased due to the campaign by the city council. Would you reject the null hypothesis at a = 0.05? Round your answer to four decimal places. p-value = We Ho- b. Make the test of part a using the critical-value approach and a = 0.05. Round your answer for z to two decimal places. Zobserved = We く Ho. We conclude that the mean consumption of water per household has eTextbook and Media く due to the campaign by the city council.

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Question 8 Assume the mean useful life of a Caterpillar motor is 500,000 hours and is normally distribut with a standard deviation of ± 50.000 hours. Calculate the percent of Caterpillar motors that last 605,000 hours or more. - 16% 0 34% 0.15% - 25%