Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P61, the 61-percentile. This is the temperature reading separating the bottom 61% from the top 39%. P61 = C Submit Question

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### Educational Module: Understanding Percentiles in Normal Distribution

**Problem Statement:**
Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find \( P_{61} \), the 61-percentile. This is the temperature reading separating the bottom 61% from the top 39%.

\[ P_{61} = \_\_\_\_\_\_^\circ C \]

**Instructions:**

1. To find \( P_{61} \), you need to determine the z-score that corresponds to the 61st percentile in the standard normal distribution.
2. Utilize z-tables or standard normal distribution calculators to find the z-score.
3. Convert the z-score to the actual temperature using the mean and standard deviation.

**Submit Answer:**
There is a submission box followed by the unit (°C) to input the calculated percentile value and a "Submit Question" button to record your answer.

**Explanation of Graphs and Diagrams:**
- No specific graphs or diagrams are present in this problem statement. In a typical normal distribution graph, the area to the left of the 61-percentile would be shaded to represent the 61% of the data.

The known parameters:
- Mean (μ) = 0°C
- Standard Deviation (σ) = 1.00°C

By solving, you can better understand the application and concept of percentiles in the normal distribution which is essential in statistical analysis.
Transcribed Image Text:### Educational Module: Understanding Percentiles in Normal Distribution **Problem Statement:** Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find \( P_{61} \), the 61-percentile. This is the temperature reading separating the bottom 61% from the top 39%. \[ P_{61} = \_\_\_\_\_\_^\circ C \] **Instructions:** 1. To find \( P_{61} \), you need to determine the z-score that corresponds to the 61st percentile in the standard normal distribution. 2. Utilize z-tables or standard normal distribution calculators to find the z-score. 3. Convert the z-score to the actual temperature using the mean and standard deviation. **Submit Answer:** There is a submission box followed by the unit (°C) to input the calculated percentile value and a "Submit Question" button to record your answer. **Explanation of Graphs and Diagrams:** - No specific graphs or diagrams are present in this problem statement. In a typical normal distribution graph, the area to the left of the 61-percentile would be shaded to represent the 61% of the data. The known parameters: - Mean (μ) = 0°C - Standard Deviation (σ) = 1.00°C By solving, you can better understand the application and concept of percentiles in the normal distribution which is essential in statistical analysis.
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