Question 7 of 8 © Macmillan Learning Alkane halogenation is a two-step reaction, as shown in the image. Using the table of bond dissociation energies, calculate the enthalpy of each step and the enthalpy of the overall reaction. > Bond Dissociation Energies (for A-BA + B) Bond broken AH (kJ/mol) Bond broken AH (kJ/mol) Bond broken AH(kJ/mol) H-H 436 400 366 292 193 Step 1 H3C- Step 2 H3C CH3 H3C CH3 CH3 CH3 Overall reaction CH3 CH3 H + + Br₂ -H+ Br₂ (CH3)3C-H (CH3)3C-Br H3C- H3C CH3 H3C- CH3 CH3 CH3 + HBr Br + CH3 Love -Br + HBr CH3 H-Br Br-Br AH = ΔΗ = ΔΗ = kJ/mol kJ/mol kJ/mol
Question 7 of 8 © Macmillan Learning Alkane halogenation is a two-step reaction, as shown in the image. Using the table of bond dissociation energies, calculate the enthalpy of each step and the enthalpy of the overall reaction. > Bond Dissociation Energies (for A-BA + B) Bond broken AH (kJ/mol) Bond broken AH (kJ/mol) Bond broken AH(kJ/mol) H-H 436 400 366 292 193 Step 1 H3C- Step 2 H3C CH3 H3C CH3 CH3 CH3 Overall reaction CH3 CH3 H + + Br₂ -H+ Br₂ (CH3)3C-H (CH3)3C-Br H3C- H3C CH3 H3C- CH3 CH3 CH3 + HBr Br + CH3 Love -Br + HBr CH3 H-Br Br-Br AH = ΔΗ = ΔΗ = kJ/mol kJ/mol kJ/mol
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:Question 7 of 8
O Macmillan Learning
Alkane halogenation is a two-step reaction, as shown in the image. Using the table of bond dissociation energies, calculate the
enthalpy of each step and the enthalpy of the overall reaction.
Bond Dissociation Energies (for A-B
Bond broken AH (kJ/mol) Bond broken AH (kJ/mol) Bond broken AĦ (kJ/mol)
H-H
436
400
366
292
193
Step 1
H3C-
Step 2
H3C-
CH3
CH3
CH3
CH3
Overall reaction
H
+
+ Br₂
CH3
I
H3C-
CH3
-H + Br₂
(CH₂)₂C-H
(CH3)3C-Br
H3C
H3C
A
H3C-
■
CH3
CH3
+
CH3
CH 3
+
-Br
CH3
F
CH3
■
B)
+ HBr
+ Br:
-Br + HBr
H-Br
Br-Br
ΔΗ =
AH =
AH =
kJ/mol
kJ/mol
kJ/mol
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