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Question 7 of 8 © Macmillan Learning Alkane halogenation is a two-step reaction, as shown in the image. Using the table of bond dissociation energies, calculate the enthalpy of each step and the enthalpy of the overall reaction. > Bond Dissociation Energies (for A-BA + B) Bond broken AH (kJ/mol) Bond broken AH (kJ/mol) Bond broken AH(kJ/mol) H-H 436 400 366 292 193 Step 1 H3C- Step 2 H3C CH3 H3C CH3 CH3 CH3 Overall reaction CH3 CH3 H + + Br₂ -H+ Br₂ (CH3)3C-H (CH3)3C-Br H3C- H3C CH3 H3C- CH3 CH3 CH3 + HBr Br + CH3 Love -Br + HBr CH3 H-Br Br-Br AH = ΔΗ = ΔΗ = kJ/mol kJ/mol kJ/mol

Question 7 of 8 © Macmillan Learning Alkane halogenation is a two-step reaction, as shown in the image. Using the table of bond dissociation energies, calculate the enthalpy of each step and the enthalpy of the overall reaction. > Bond Dissociation Energies (for A-BA + B) Bond broken AH (kJ/mol) Bond broken AH (kJ/mol) Bond broken AH(kJ/mol) H-H 436 400 366 292 193 Step 1 H3C- Step 2 H3C CH3 H3C CH3 CH3 CH3 Overall reaction CH3 CH3 H + + Br₂ -H+ Br₂ (CH3)3C-H (CH3)3C-Br H3C- H3C CH3 H3C- CH3 CH3 CH3 + HBr Br + CH3 Love -Br + HBr CH3 H-Br Br-Br AH = ΔΗ = ΔΗ = kJ/mol kJ/mol kJ/mol

Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter10: Energy
Section: Chapter Questions
Problem 6QAP: n Fig. 10.1, what kind of energy does ball A possess initially when at rest at the top of the hill?...
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Question 7 of 8 O Macmillan Learning Alkane halogenation is a two-step reaction, as shown in the image. Using the table of bond dissociation energies, calculate the enthalpy of each step and the enthalpy of the overall reaction. Bond Dissociation Energies (for A-B Bond broken AH (kJ/mol) Bond broken AH (kJ/mol) Bond broken AĦ (kJ/mol) H-H 436 400 366 292 193 Step 1 H3C- Step 2 H3C- CH3 CH3 CH3 CH3 Overall reaction H + + Br₂ CH3 I H3C- CH3 -H + Br₂ (CH₂)₂C-H (CH3)3C-Br H3C H3C A H3C- ■ CH3 CH3 + CH3 CH 3 + -Br CH3 F CH3 ■ B) + HBr + Br: -Br + HBr H-Br Br-Br ΔΗ = AH = AH = kJ/mol kJ/mol kJ/mol
Transcribed Image Text:Question 7 of 8 O Macmillan Learning Alkane halogenation is a two-step reaction, as shown in the image. Using the table of bond dissociation energies, calculate the enthalpy of each step and the enthalpy of the overall reaction. Bond Dissociation Energies (for A-B Bond broken AH (kJ/mol) Bond broken AH (kJ/mol) Bond broken AĦ (kJ/mol) H-H 436 400 366 292 193 Step 1 H3C- Step 2 H3C- CH3 CH3 CH3 CH3 Overall reaction H + + Br₂ CH3 I H3C- CH3 -H + Br₂ (CH₂)₂C-H (CH3)3C-Br H3C H3C A H3C- ■ CH3 CH3 + CH3 CH 3 + -Br CH3 F CH3 ■ B) + HBr + Br: -Br + HBr H-Br Br-Br ΔΗ = AH = AH = kJ/mol kJ/mol kJ/mol
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