Question 7 Listen A bacterial cell divides in the presence 32P, which is a radioactive isotope of phosphorous. This atom becomes part of the phosphate which is in DNA. After the first division, the bacteria is switched into a growth medium in which the phosphorous is not radioactive and is kept in this media for the rest of the experiment. The bacterial cell divides until there are 8 cells. How many of these cells will be radioactive? a) 0 b) 1 c) 2 d) 4 e) 8

Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
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Question 7

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A bacterial cell divides in the presence 32P, which is a radioactive isotope of
phosphorous. This atom becomes part of the phosphate which is in DNA. After the
first division, the bacteria is switched into a growth medium in which the
phosphorous is not radioactive and is kept in this media for the rest of the
experiment. The bacterial cell divides until there are 8 cells. How many of these cells
will be radioactive?
a) 0
b) 1
c) 2
d) 4
e) 8
Transcribed Image Text:Question 7 Listen A bacterial cell divides in the presence 32P, which is a radioactive isotope of phosphorous. This atom becomes part of the phosphate which is in DNA. After the first division, the bacteria is switched into a growth medium in which the phosphorous is not radioactive and is kept in this media for the rest of the experiment. The bacterial cell divides until there are 8 cells. How many of these cells will be radioactive? a) 0 b) 1 c) 2 d) 4 e) 8
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