Please refer to the attached pic. Calculate the pressure gauage and absolute at depth of water density is 1000 kg/m3 QUESTION 7Calculate the pressure (gauge and absolute) at depth of water (density 1000 kg/m2).Depth of WaterGauge PressureAbsolute Pressure(in Pascal)(in Pascal)100 mB.200 mD.300mE.F.500mG.H.v A.A. -1081990 Pav RClick Save and Submit to save and submit. Click Save All Answers to save all answers.ype here to searchWA.C.

Name: Please refer to the attached pic. Calculate the pressure gauage and ab
Uploaded: 2024-03-20T06:51:10.000Z
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Description: Please refer to the attached pic. Calculate the pressure gauage and absolute at depth of water density is 1000 kg/m3 QUESTION 7Calculate the pressure (gauge and absolute) at depth of water (density 1000 kg/m2).Depth of WaterGauge PressureAbsolute Pre

Given values: Density of water, ρ=1000 kg/m3 Acceleration due to gravity, g=9.8 m/s2 Normal atmospheric pressure, Patm=101325 PaThe pressure measured relative to free space is called absolute pressure (Pabs) and the difference between absolute pressure and atmospheric pressure (Patm) is called guage pressure (Pgauge). Mathematically, Pabs=Pgauge+Patm...(1) The gauge pressure is given by, Pgauge=ρgh...(2) Where, ρ=Densityg=Acceleration due to gravityh=Height A) For depth of the water, h=100 m gauge pressure is found by using equation (2). Pgauge=1000 kg/m3×9.8 m/s2×100 m=980000 Pa B) Found absolute pressure at h=100 m by using equation (1). Pabs=980000 Pa+101325 Pa=1081325 Pa C) For depth of the water, h=200 m gauge pressure is found by using equation (2). Pgauge=1000 kg/m3×9.8 m/s2×200 m=1960000 Pa D) Found absolute pressure at h=200 m by using equation (1). Pabs=1960000 Pa+101325 Pa=2061325 Pa E) For depth of the water, h=300 m gauge pressure is found by using equation (2). Pgauge=1000 kg/m3×9.8 m/s2×300 m=2940000 Pa F) Found absolute pressure at h=300 m by using equation (1). Pabs=2940000 Pa+101325 Pa=3041325 Pa G) For depth of the water, h=500 m gauge pressure is found by using equation (2). Pgauge=1000 kg/m3×9.8 m/s2×500 m=4900000 Pa H) Found absolute pressure at h=500 m by using equation (1). Pabs=4900000 Pa+101325 Pa=5001325 Pa Answer: Depth of water Gauge pressure (In pascal) Absolute pressure (In pascal) 100 m A.980000 B.1081325 200 m C.1960000 D.2061325 300 m E.2940000 F.3041325 500 m G.4900000 H.5001325