Question 6 The IBP formula fudv=uv - fvdu can also be written as fudv+fvdu = uv Which of the following statements fits and satisfies the equations? S(2x + 3) sec² (1) dx - f 4 tan (1) dx = 2(2x + 3) tan ( () A S(2x + 3) csc² (1) dx + f 4 tan (2) dx = 2(2x + 3) cot (1) B) S(2x + 3) sec² (1) dx + f 4 cot (1) dx = −2(2x + 3) tan ( ((2x + 3) csc² (²) dx - [ 4 cot (²) dx = −2(2x + 3) cot (2) :
Question 6 The IBP formula fudv=uv - fvdu can also be written as fudv+fvdu = uv Which of the following statements fits and satisfies the equations? S(2x + 3) sec² (1) dx - f 4 tan (1) dx = 2(2x + 3) tan ( () A S(2x + 3) csc² (1) dx + f 4 tan (2) dx = 2(2x + 3) cot (1) B) S(2x + 3) sec² (1) dx + f 4 cot (1) dx = −2(2x + 3) tan ( ((2x + 3) csc² (²) dx - [ 4 cot (²) dx = −2(2x + 3) cot (2) :
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Question 6
=
The IBP formula fudv=uv-fvdu can also be written as f udv + f vdu:
Which of the following statements fits and satisfies the equations?
S(2x + 3) sec² (1) dx − f 4 tan (₹) dx = 2(2x + 3) tan (
(*)**
S(2x + 3) csc² (1) dx + f 4 tan (1) dx = 2(2x + 3) cot (
(5)
B
S(2x + 3) sec² (1) dx + √ 4 cot (1) dx = −2(2x + 3) tan (2)
(2x + 3) csc² (1) dx − f 4 cot (1) dx = −2(2x + 3) cot (
ot (1)
(A)
D
uv
:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3bd745b7-2075-4d56-a286-f77c7f48f0ee%2F044eb884-f86a-4b59-8374-c5664d40652e%2Fy5dnpmq_processed.png&w=3840&q=75)
Transcribed Image Text:Question 6
=
The IBP formula fudv=uv-fvdu can also be written as f udv + f vdu:
Which of the following statements fits and satisfies the equations?
S(2x + 3) sec² (1) dx − f 4 tan (₹) dx = 2(2x + 3) tan (
(*)**
S(2x + 3) csc² (1) dx + f 4 tan (1) dx = 2(2x + 3) cot (
(5)
B
S(2x + 3) sec² (1) dx + √ 4 cot (1) dx = −2(2x + 3) tan (2)
(2x + 3) csc² (1) dx − f 4 cot (1) dx = −2(2x + 3) cot (
ot (1)
(A)
D
uv
:
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