Evaluate | sin2x tan (sinx)dx

Q: tan Ź t Sin Ź

A:

Q: Simplify tan (-x) ese(x) cos(x)= А. О В. 1 С. -1 D. sinx

A: tan(-x) cosec (x) cos (x) = [Sin(-x)/ cos(-x)] cosec (x) cos(x)  = [sin (-x)/cos (x) ] cosec (x) cos…

Q: Complete the identity. sin'x (cscx+ se2x) = sec2x X. CS sec-x

A: To show: sin2x(csc2x+sec2x)=sec2x Solution: Considering LHS sin2x(csc2x+sec2x) On simplifying…

Q: 8. Find the exact value. sin(tan¬1 x)

A: Convert tan-1x into sin-1x then calculate exact value

Q: (A) Evaluate Sin (3x) Sin (3x) dx

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Q: Establish the identity. sin =1- sin x

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Q: Simplify sin sin(T - x) + sin sin(21- x). + 2 2

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Q: Evaluate 13 sin(x) cos(x) dx

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Q: Evaluate sin 2x -dx sin x sin x+- 3 3

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Q: Differentiate  (sin(x+a)/cosx)

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Q: Write ( tan(x) + sec(x)) ( sin( x) - 1) in terms of sine and cosine.

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Q: Evaluate sin dx

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Q: Prove the identity. sin x+ 2. = cotx sin (n-x)

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Q: Write ∫ tan3 x dx in terms of ∫ tan x dx. Then find ∫ tan3 x dx.

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Q: Find 7 sin (7x) dx

A: According to question,Given Integral,Let I = ∫7 sin27x dx

Q: Verify the identity: tan(-x)cos x = -sin x

A: To verify:      tan(-x)cos x = -sin x We will start from LHS and will try to get RHS.

Q: Write sin (2 tan-1 x) as an equivalent algebraic expression involv-ing only x. (Assume x is…

A: Let tan-1x=uTherefore, tan u=x1And tan u=oppositeadjacentSo, Opposite=xAdjacent=1And…

Q: Rewrite the expression as an algebraic expression in x. tan(sin-1(x))

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Q: Evaluate  ∫ππsin2x Cos4x dx .

A: Since the upper limit = the lower limit  So the value of the function will be 0

Q: Find sin 0.

A:

Q: Verify the identity sin 2t - tan t = tan t cos 2t.

A: Given:sin2t-tant=tant cos2tTrigonometry formula:sin2t=2sint costtant=sintcostcos2t=cos2t-sin2t

Q: Find sin x if sin x – cos x x = 3 sec x

A: Consider the given trigonometric expression, sinx-cosx=13 now square both side of the equation,…

Q: tan x= Sin 2X

A: Given: y'+y tan x= sin2x

Q: sinx.cosx 1- Sin?x

A:

Q: Evaluate: / [cos(x) – sin(x)]dr

A: To find:∫cosx-sinxdx

Q: cosx + + sin x 3

A:

Q: Sinx=2/3 Cosx=? Tanx=?

A: Question is solved.

Q: Evaluate sin (5x) dx.

A: We have to find the given integration. We will do this integration by using substitution.

Q: . Evaluate sin (x) cos(x)dr using an appropriate substitution.

A: According to our answering guidelines we can only answer one question at time, therefore I am…

Q: sin (플 + z) + sin (-a) is equivalent to: 4

A: Given the trigonometric identitysin(π4+x)+sin(π4−x)

Q: 3. sinx tan x + cos x

A: We can simplify the expression as below.

Q: 2. Describe a way of evaluating sin° x dx.

A:

Q: Verify the identity. tan (-x) cos x= - sin x

A: This question is based on Trignometric function.

Q: Find sin X os X

A:

Q: Verify the identity: sinx + secx        = sinxcosx + 1       secx

A: To verify,

Q: Simplify: tanx sinx + cosx=

A: tanx sinx + cosx = secx

Q: Verify the identity. tan (-x) cos X - sin x

A:

Q: Complete the identity. 2. sinx+tan´x+cos x=?

A: complete the identity               sin2x + tan2x +cos2x=

Q: Rewrite sin x + in terms of sin(x) and 4 cos(x).

A: Recall:  sin(A+B)=sin A cos B+sin B cos A We have, A=x, B=5π4

Q: Rewrite sin (x + in terms of sin x and cos x. 6.

A:

Q: Differentiate sin x? +1

A: According to the question,  We need to differentiate the function,  Function: sin x2 +1

Q: Evaluate  sin2x*cos2x dx

A: Given that: ∫sin2x.cos2x.dx

Q: Simplify tanx (cscx sinx). A B D 0 1 sinx COSX

A:

Q: Use reciprocal and quotient identities to find the value. V21 2/3 1. If tanx: 3 and secx = find…

A: Given that

Q: Verify the identity: sin x tan x + cos x = sec x.

A: Given:sinx tanx+cosx=secx

Q: write cos x in terms of tan x  1 + tan2 x = sec2 x

A: We write cos x in terms of tan x    1 + tan2 x = sec2 x

Q: cosx+1=sinx

A:

Q: Use the identities to find sinx and tanx if secx 2 and sinx < 0. %3D

A: Given that sec x = 2 and sin x &lt;0 we need to find value of sin x and tan x

Fundamentals of Trigonometric Identities

Trigonometric Identities are the equalities that involve trigonometry functions and hold for all the values of variables given in the equation.