Question 6- Slab Design The stability of the following needs to be checked. Design the wall based on the following data: Soil Data: Retaining Wall Data: Unit weight of soil y,= 17 KN/m3 Top of Stem: 0.3 m Unit weight of concrete y. 24 KN.. m3 Bottom of Stem: 0.4 m Internal angle of friction o = 36° Length of Toe: 0.4 m Coefficient of friction between concrete bases Length of footing base: 2.0 m and soil u = 0.55 Bearing capacity of the soil qu = 300 KN/m² Thickness of footing: 0.3 m Height of the retaining wall: 2.85m Calculate: a. Sketch the proportions of the wall b. Factor of safety against sliding c. Factor of safety against overturning. d. Factoring of safety against subsiding

Q: The ∑ F proceeding in the couple is?

A: Brief concept- Couple- It is a pair of equal and opposite parallel forces. These two forces do not…

Q: 1. GIVEN: REQOIREO: yo l0". 7,9 to locete the centreid t 6"

A: To find centroid

Q: 6 in Gin Gin 9 in 3in

A: Schematic diagram of the given problem:

Q: A C L- (2) B "1-12- -L/2→ C x

A:

Q: Determine y for the area shown y 1" 1" in .5" 1" 2" 2" X

A:

Q: hat about pin d?

A: We know that Forces acting at Joint D are shown in figure below Forces moving away from joints are…

Q: Problem 3: A bracket of negligible weight shown in the figure below is loaded a force of 13.34 kN.…

A:

Q: show the (c)

A:

Q: Problem 12.16 Consider the building frame shown in (Eure) Suppose that My 2.6 k/ft and s8 k/ft.…

A:

Q: 4) A precast T beam with the dimensions shown below is to be a used as a bridge over a small…

A: As per Bartleby's guidelines we are supposed to answer only first three questions. Kindly repost…

Q: Figure 2. Inside perimeter Outside perimeter Centreline

A: Inside perimeter :Length×2+Breadth×2+2×2'+3'24'3''×2+12'×2+2×2'+3'=79'6''

Types of Composite

Composite materials are formed by merging two components that have different chemical and physical properties. The merged output is termed as a composite, whose properties are completely different from the individual components. Composite materials also have better strength than the individual components.Composite materials usually have two main parts, reinforcement material, and matrix material. The matrix material acts as a binder and surrounds the fiber of another material that bears a much higher strength. This material is known as the reinforcement material. The matrix materials are usually high-strength additives resins, while the fibers of the reinforced material can be random, oriented, and in a mat format.Composite materials are also known as fiber-reinforced composite polymers because they are composed of the polymer matrix which is reinforced to laboratory-created fibers or naturally occurring fibers, such as glass fibers, carbon fibers, or aramid fibers. Under the application of external loads, the matrix material absorbs and transfers the loads to the fibers, these fibers in return provide good compressive strength, tensile strength, and stiffness to the fiber-reinforced composite materials.Depending upon the matrix and the reinforcement material, different properties can be induced to the fiber-reinforced composite materials, including good corrosion resistance properties. The most common matrix material is the resin while the glass fibers act as the reinforcement material. Strong fibers provide strength and stiffness to the composite materials while, a soft and flexible resin provides shape to the composite materials.