QUESTION 6 Marketers believe that more than 67% of adults in UAE own an iPhone. The appropriate null and alternative hypotheses are Ho: p ≤ 0.67 vs Ha: p > 0.67. Ho:p>0.67 vs H:p≤0.67. Ho: p=0.67 vs H₂:p*0.67. Ho: p20.67 vs H:p<0.67.
Q: Suppose the dietician conducted his study and found a p-value of 0.085. Based on this p-value, what…
A: Given : p -value = 0.085
Q: A random sample of 865 births included 432 boys. Use a 0.05 significance level to test the claim…
A: Denote p as the true proportion of new born babies, who are boys.
Q: A random sample of 845 births included 435 boys. Use a 0.10 significance level to test the claim…
A: given data n = 845x = 435p^ = xn = 435845 = 0.51claim:p=0.505
Q: the proportion of wildfires caused by humans in the south lower than the proportion of wildfires…
A:
Q: State the null and alternative hypotheses b. Perform a paired samples t test with the descriptive…
A: Given Information: Given that, Students want to test claim that Students tend to make more mistakes…
Q: A local chess club claims that the length of time to play a game has a mean of 58 minutes or more.…
A: Claim: A local chess club claims that the length of time to play a game has a mean of 58 minutes or…
Q: The average number of accidents at controlled intersections per year is 5.3. Is this average a…
A:
Q: Suppose the manager conducted her study and found a p-value of 0.02. Based on this p-value, what…
A: Suppose the manager conducted her study and found a p-value of 0.02.
Q: A researcher examines 61 critically ill patients with myxedema coma. He wishes to determine if the…
A: We have given that a researcher examines 61 critically ill patients with myxedema coma.The scenario…
Q: Suppose 212 subjects are treated with a drug that is used to treat pain and 52 of them developed…
A: Correct answer: Option (B)
Q: Suppose 233subjects are treated with a drug that is used to treat pain and 50 of them developed…
A: One sample proportion: One sample proportion test is used to compare the proportion of values in…
Q: eviously, 7.9% of workers had a travel time to work of more than 60 minutes. An urban economist…
A: Given N=85 X=15
Q: Suppose 204 subjects are treated with a drug that is used to treat pain and 55 of them developed…
A:
Q: What is Curvilinear Relationship?
A:
Q: f a hypothesis test is performed, how should you conclude a decision that fails to reject the null…
A: Here Given mean age of bus driver is 50.2 years
Q: A consumer group believes that more than 30% of Filipinos owns more than 2 cellphones. They surveyed…
A: Given: Let p denotes the population proportion of Filipinos who owns more than 2 cellphones.…
Q: Consider a drug testing company that provides a test for marijuana usage. Among 253 tested subjects,…
A:
Q: A hypothesis test is to be performed. Determine the null and alternative hypotheses. In the past,…
A: Solution: The hypothesis can be classified into two types 1) Null hypothesis 2)Alternative…
Q: A study on crimes made a statement that at least 35% of all arsonists were under 21 years of age.…
A:
Q: within six years. Is this percent smaller than for students who play intramural sports? 155 of the…
A:
Q: USA Today reported that about 47% of the general consumer population in the United States is loyal…
A: (a) The level of significance is 0.01. Hypotheses: H0:p=0.45; H1:p>0.47
Q: Marketers believe that 65.94% of adults in the U.S. own a cell phone. A cell phone manufacturer…
A: To testH0:p=0.6594H1:p≠0.6594
Q: In a program designed to help patients stop smoking, 163 patients were given sustained care, and…
A:
Q: As a result of complaints from customers about delivery times, the manager at a pizza delivery…
A: GivenThe manager believed the delivery time was 20 minutesThe manager at a pizza delivery serive is…
Q: Suppose 241 subjects are treated with a drug that is used to treat pain and 50 of them developed…
A: The sample size is .The number of successes in the sample is .The hypothesized proportion is .The…
Q: 11% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of…
A: For the given data Perform Z test for one population proportion
Q: s the proportion of wildfires caused by humans in the south lower than the proportion of wildfires…
A: Solution: Given information: n1= 562 Sample size of wildfires in south n2= 548 Sample size of…
Q: A random sample of 872births included 432 boys. Use a 0.10 significance level to test the claim that…
A:
Q: The recidivism rate for convicted sex offenders is 11%. A warden suspects that this percent is lower…
A:
Q: A random sample of 845 births included 435 boys. Use a 0.10 significance level to test the claim…
A: Solution: Given information: n = 845= Sample size of birth x = 435 boys p^=xn=435845= 0.5148…
Q: A sample of 100 flounder have a sample mean weight of 21.5 grams. Scientists wish to perform a…
A: Solution: Here, it is to be determined that if the mean weight differs from 20 grams. State the…
Q: magazine reported that at the top 50 business schools in a region, students studied an average of…
A: Given that : A magazine reported that at the top 50 business schools in a region, students studied…
Q: A researcher thinks that the mean starting salary for San Jose State University graduates is under…
A: Claim: The mean starting salary for San Jose State University graduates is under $100,000 per year…
Q: A random sample of 844 births included 431 boys. Use a 0.10 significance level to test the claim…
A: Given : Let X : No. of births boys Sample size (n) = 844 X = 431 α = 0.10
Q: A manager states that in his warehouse, the average number of days per year missed by the employees…
A:
Q: USA Today reported that about 47% of the general consumer population in the United States is loyal…
A: We have given that the hypothetical proportion p0=0.47, sample size 1002 and favourable cases X =…
Q: In a program designed to help patients stop smoking, 177 patients were given sustained care, and…
A: Solution: From the given information, p-hat=0.836 and n=177.
Q: Suppose 247 subjects are treated with a drug that is used to treat pain and 52 of them developed…
A: Given: Sample size (n) = 247 Number of subjects developed nausea (x) = 52 Hypothesized proportion…
Q: Suppose a professional basketball player historically makes 39% of his three-point field goals.…
A: When the variable of interest is categorical in nature, it indicates that we are dealing with the…
Q: A random sample of 847 births included 434 boys. Use a 0.10 significance level to test the claim…
A: Given that Sample size (n) = 847 Number of boys (x) = 434 Sample proportion (p) = 434847=0.5124…
Q: A random sample of 855 births included 431 boys. Use a 0.05 significance level to test the claim…
A: Solution: State the hypotheses Null hypothesis: H0: p=0.515 That is, the proportion of new born…
Q: Previously, 5.5% of workers had a travel time to work of more than 60 minutes. An urban economist…
A: Solution: We have give that 5.5% of workers had a travel time to work of more than 60 minutes.
Q: Previously, 9.8% of workers had a travel time to work of more than 60 minutes. An urban economist…
A:
Step by step
Solved in 2 steps
- The recidivism rate for convicted sex offenders is 8%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 321 convicted sex offenders who were also drug addicts, 22 of them became repeat offenders. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? Select an answer (please enter a decimal) H1: ? 0 Select an answer > (Please enter a decimal) c. The test statistic ? o (please show your answer to 3 decimal places.)The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65-74 years: n-118, x- 12.2, and s-6.96, Does this data indicate that average daily zinc intake in the population of all males age 65-74 falls below the recommended allowance? (Use a -0.05.) State the appropriate null and alternative hypotheses, ⒸHR=15 OH₂ = 15 H₂p=15 H₂ <15 ⒸH-15 H₁ s 15 Calculate the test statistic and determine the P-valde (Round your test statistic to two decimal places and your P-value to four decimalYou may need to use the appropriate appendix table to answer this question. Suppose that the average price for a gallon of gasoline in the Country A is $3.74 and in Country B it is $3.40. Assume these averages are the population means in the two countries and that the probability distributions are normally distributed with a standard deviation of $0.25 in the Country A and a standard deviation of $0.20 in Country B. (a) What is the probability that a randomly selected gas station in Country A charges less than $3.50 per gallon? (Round your answer to four decimal places.) (b) What percentage of the gas stations in Country B charge less than $3.50 per gallon? (Round your answer to two decimal places.) (c) What is the probability that a randomly selected gas station in Country B charged more than the mean price in the Country A? (Round your answer to four decimal places.)
- USA Today reported that about 47% of the general consumer population in the United States is loyal to the automobile manufacturer of their choice. Suppose Chevrolet did a study of a random sample of 1008 Chevrolet owners and found that 487 said they would buy another Chevrolet. Does this indicate that the population proportion of consumers loyal to Chevrolet is more than 47%? Use ? = 0.01. (a) What is the level of significance?State the null and alternate hypotheses. H0: p > 0.47; H1: p = 0.47H0: p = 0.47; H1: p ≠ 0.47 H0: p = 0.47; H1: p < 0.47H0: p = 0.47; H1: p > 0.47 (b) What sampling distribution will you use? The standard normal, since np < 5 and nq < 5.The standard normal, since np > 5 and nq > 5. The Student's t, since np < 5 and nq < 5.The Student's t, since np > 5 and nq > 5. What is the value of the sample test statistic? (Round your answer to two decimal places.)(c) Find the P-value of the test statistic. (Round your answer to four…A researcher hypothesizes that performance on a cognitive test will be better when people have had a full night's sleep compared to when these same people are sleep deprived. A sample of 12 people is deprived of sleep for one night before taking the test. Under these circumstances, the mean number of questions they answered correctly was 6.08 with an SD of 1.38. A week later, these same people complete the test afler a full night's sleep. The mean number of questions answered correctly under these circumstances was 14.25 with an SD of 3.7. The raw scores and Z-scores were as follows: 3. No Sleep 0 66 139 Sleep 16 0.47 19 1 29 0.20 0 20 -0.07 0 20 -0.34 0.66 15 1.39 15 -0.79 14 15 0.06 0.06 -0.79 13 12 -0.61 -2.77 0 20 3. -2.24 4. -0.06 15 6. -0.06 16 047 -0.06 17 0.74 Test the researcher's hypothesis at a -05.Past studies have indicated that the percentage of smokers was estimated to be about 34%. Given the new smoking cessation programs that have been implemented, you now believe that the percentage of smokers has reduced. You randomly surveyed 1708 people and found that 544 smoke. Use a 0.05 significance level to test the claim that the percentage of smokers has reduced.a) Identify the null and alternative hypotheses?H0H0: H1H1: b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)? left-tailed right-tailed two-tailed c) Identify the appropriate significance level.d) Calculate your test statistic (Use ˆpp^ rounded to 4 decimal places). Write the result below, and round your test statistic to 4 decimal places.e) Calculate your p-value. Write the result below, rounded to four decimal places.f) Do you reject the null hypothesis? We reject the null hypothesis, since the p-value is less than the significance level. We reject the…
- Suppose 206 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance level to test the claim that more than 20% of users develop nausea. Identify the null and alternative hypotheses for this test. Choose the correct answer below. OA. Ho: p=0.20 H₁: p0.20 OC. Ho:p>0.20 H₁: p=0.20 OD. Ho: p=0.20 H₁: p0.20 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. A. Fail to reject Ho. There is sufficient evidence to warrant support of the claim that more than 20% of users develop nausea. OB. Fail to reject Ho. There is not sufficient evidence to warrant support of the claim that more than 20% of users develop nausea. OC. Reject Ho. There is sufficient evidence to warrant…More than 59% of adults would erase all their personal information. The hypothesis test results in a p value of .0241. State a conclusion about the null hypothesis. Without using technical terms state a final conclusionIn a program designed to help patients stop smoking, 213 patients were given sustained care, and 83.6% of them were no longer smoking after one month. Use a 0.05 significance level to test the claim that 80% of patients stop smoking when given sustained care. Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. H0: p=0.8 H1: p<0.8 B. H0: p=0.8 H1: p≠0.8 Your answer is correct. C. H0: p≠0.8 H1: p=0.8 D. H0: p=0.8 H1: p>0.8 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is- The p-value- Reject Ho?
- Past studies have indicated that the percentage of smokers was estimated to be about 35%. Given the new smoking cessation programs that have been implemented, you now believe that the percentage of smokers has reduced. You randomly surveyed 2405 people and found that 799 smoke. Use a 0.05 significance level to test the claim that the percentage of smokers has reduced.a) Identify the null and alternative hypotheses?H0H0: H1H1: b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)? left-tailed right-tailed two-tailed c) Identify the appropriate significance level.d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal places.e) Calculate your p-value. Write the result below, and be sure to round your final answer to four decimal places.f) Do you reject the null hypothesis? We reject the null hypothesis, since the p-value is less than the significance level. We reject the…The mean number of eggs per person eaten in the United States is 266. Do college students eat a different number of eggs than the average American? The 61 college students surveyed averaged 285 eggs per person and their standard deviation was 72.6. What can be concluded at the a= 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: v Select an answer H.: vSelect an answer c. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value = e. The p-value is ? f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) a O The data suggest that the sample mean is not significantly different from 266 at a = 0.10, so there is statistically insignificant evidence to conclude that the sample mean number of eggs consumed by college students per year is different from 285. O The data suggest that the…In the past, the mean running time for a certain type of flashlight battery has been 9.6 hours. The manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has decreased as a result. A hypothesis test is to be performed. Determine the null and alternative hypotheses. A. H0: µ ¥ 9.6 hours and H1: µ = 9.6 hours B. H0: µ = 9.6 hours and H1: µ ¥ 9.6 hours C. H0: µ = 9.6 hours and H1: µ > 9.6 hours D. H0: µ = 9.6 hours and H1: µ < 9.6 hours
