Question 6 Hint 1 Hint 2 Suppose you walk 23 m straight west and then 14 m straight north. Answer all questions assuming the + x - axis is to the east. < > • How far are you from your starting point? D = m = • What is your displacement vector? Ax x + y) m • What is the direction of your displacement? 0 = degrees relative to the + x - axis.
Question 6 Hint 1 Hint 2 Suppose you walk 23 m straight west and then 14 m straight north. Answer all questions assuming the + x - axis is to the east. < > • How far are you from your starting point? D = m = • What is your displacement vector? Ax x + y) m • What is the direction of your displacement? 0 = degrees relative to the + x - axis.
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Question 6
Suppose you walk 23 m straight west and then 14 m straight north. Answer all questions assuming the \( +x \) - axis is to the east.
- **How far are you from your starting point?**
\[ D = \boxed{ \ \ \ \ \ \ \ \ } \text{ m} \]
- **What is your displacement vector?**
\[ \Delta \vec{x} = (\boxed{ \ \ \ \ \ \ \ \ } \hat{x} + \boxed{ \ \ \ \ \ \ \ \ } \hat{y}) \text{ m} \]
- **What is the direction of your displacement?**
\[ \theta = \boxed{ \ \ \ \ \ \ \ \ } \text{ degrees relative to the } +x \text{ - axis.} \]
#### Hints
- [Hint 1](#)
- [Hint 2](#)
### Explanation:
In this problem, you are required to calculate the overall displacement and direction after walking a certain distance west and north from your starting point.
The "+x" axis is to the east, which means west corresponds to the negative x-direction and north corresponds to the positive y-direction.
1. **Distance from starting point (D)**: This can be found using the Pythagorean theorem where the legs of the right triangle are 23 m and 14 m.
2. **Displacement Vector (\(\Delta \vec{x}\))**: This vector is expressed in terms of its x-component and y-component. Walking west 23 m gives an x-component of -23, and walking north 14 m gives a y-component of +14.
3. **Direction (\(\theta\))**: The direction of the vector can be found using trigonometry, specifically the arctangent function, to find the angle of the displacement vector relative to the positive x-axis.
Please replace the boxed spaces with your calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33eba9e5-eb7d-44a1-93e3-ed0ee897e17f%2F71869c59-2ca8-4213-b980-c4003f58c412%2Fyjvwyqi_processed.png&w=3840&q=75)
Transcribed Image Text:### Question 6
Suppose you walk 23 m straight west and then 14 m straight north. Answer all questions assuming the \( +x \) - axis is to the east.
- **How far are you from your starting point?**
\[ D = \boxed{ \ \ \ \ \ \ \ \ } \text{ m} \]
- **What is your displacement vector?**
\[ \Delta \vec{x} = (\boxed{ \ \ \ \ \ \ \ \ } \hat{x} + \boxed{ \ \ \ \ \ \ \ \ } \hat{y}) \text{ m} \]
- **What is the direction of your displacement?**
\[ \theta = \boxed{ \ \ \ \ \ \ \ \ } \text{ degrees relative to the } +x \text{ - axis.} \]
#### Hints
- [Hint 1](#)
- [Hint 2](#)
### Explanation:
In this problem, you are required to calculate the overall displacement and direction after walking a certain distance west and north from your starting point.
The "+x" axis is to the east, which means west corresponds to the negative x-direction and north corresponds to the positive y-direction.
1. **Distance from starting point (D)**: This can be found using the Pythagorean theorem where the legs of the right triangle are 23 m and 14 m.
2. **Displacement Vector (\(\Delta \vec{x}\))**: This vector is expressed in terms of its x-component and y-component. Walking west 23 m gives an x-component of -23, and walking north 14 m gives a y-component of +14.
3. **Direction (\(\theta\))**: The direction of the vector can be found using trigonometry, specifically the arctangent function, to find the angle of the displacement vector relative to the positive x-axis.
Please replace the boxed spaces with your calculations.
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