QUESTION 6 Given the following equilibrium constants, CdCO3 Ksp = 1.0 x 10-12 and Cd(NH3)42+ Kf = 1.3 × 107, determine Ke for the dissolution of CdCO3 in aqueous ammonia (shown below). CdCO3(s) + 4 NH3(aq) = Cd(NH3)42+ (aq) + CO3(aq) 1.3 × 1019 7.7 x 10-20 8.7 x 10-12 8.7 x 10-10 1.3 × 10-5 O
QUESTION 6 Given the following equilibrium constants, CdCO3 Ksp = 1.0 x 10-12 and Cd(NH3)42+ Kf = 1.3 × 107, determine Ke for the dissolution of CdCO3 in aqueous ammonia (shown below). CdCO3(s) + 4 NH3(aq) = Cd(NH3)42+ (aq) + CO3(aq) 1.3 × 1019 7.7 x 10-20 8.7 x 10-12 8.7 x 10-10 1.3 × 10-5 O
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![QUESTION 6
Given the following equilibrium constants,
CdCO3 Ksp = 1.0 x 10-12 and Cd(NH3)42+ Kf = 1.3 x 107,
determine Kc for the dissolution of CdCO3 in aqueous ammonia (shown below).
CdCO3(s) + 4 NH3(aq) = Cd(NH3)42+ (aq) + CO3(aq)
1.3 x 1019
7.7 x 10-20
8.7 x 10-12
8.7 x 10-10
O
1.3 x 10-5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec4b7167-da6a-4aa3-84cf-e7d9abdd47b2%2F2221bafc-ac1f-47fe-a056-664d9b22a0e0%2Feh6azie_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 6
Given the following equilibrium constants,
CdCO3 Ksp = 1.0 x 10-12 and Cd(NH3)42+ Kf = 1.3 x 107,
determine Kc for the dissolution of CdCO3 in aqueous ammonia (shown below).
CdCO3(s) + 4 NH3(aq) = Cd(NH3)42+ (aq) + CO3(aq)
1.3 x 1019
7.7 x 10-20
8.7 x 10-12
8.7 x 10-10
O
1.3 x 10-5
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