A solution is prepared by adding 0.16 mole of Ni(NH3)6 Cl2 to 0.50 L of 3.5 M NH3. Calculate [Ni (NH3)²+]6²+] and2+in this solution. Koverall for Ni (NH3)65.5 × 108-for the overall reaction2+[Ni (NH3)²+] = [[N₁²+] = [Ni (NH3) 6[Ni²+ ][NH3]62+Ni²+ (aq) + 6NH3(aq) ⇒ Ni (NH3)²+ (aq)M2+Mis 5.5 × 108. That is,

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A solution is prepared by adding 0.16 mole of Ni (NH3)6 Cl₂ to 0.50 L of 3.5 M NH3. Calculate Ni (NH3)6² and 2+ in this solution. Koverall for Ni (NH3)6² is 5.5 x 108. That is, 5.5 × 108 for the overall reaction Ni (NH3)62 [Ni+][NH 2+ [Ni(NH3),*] -[ [Ni²+]-[ 2+ = 2+ Ni²+ (aq) + 6NH3(aq) ⇒ Ni (NH3)6 ²+ M M 2+ (aq)

A solution is prepared by adding 0.16 mole of Ni (NH3)6 Cl₂ to 0.50 L of 3.5 M NH3. Calculate Ni (NH3)6² and 2+ in this solution. Koverall for Ni (NH3)6² is 5.5 x 108. That is, 5.5 × 108 for the overall reaction Ni (NH3)62 [Ni+][NH 2+ [Ni(NH3),*] -[ [Ni²+]-[ 2+ = 2+ Ni²+ (aq) + 6NH3(aq) ⇒ Ni (NH3)6 ²+ M M 2+ (aq)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A solution is prepared by adding 0.16 mole of Ni(NH3)6 Cl2 to 0.50 L of 3.5 M NH3. Calculate [Ni (NH3)²+]
6²+] and
2+
in this solution. Koverall for Ni (NH3)6
5.5 × 108
-
for the overall reaction
2+
[Ni (NH3)²+] = [
[N₁²+] = [
Ni (NH3) 6
[Ni²+ ][NH3]6
2+
Ni²+ (aq) + 6NH3(aq) ⇒ Ni (NH3)²+ (aq)
M
2+
M
is 5.5 × 108. That is,

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