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If 150 mL 0.0180 M Ni(NO3)2 and 125 mL of 0.25 M ammonia (NH₂) are diluted to 500 mL with deionized water. What is the concentrations of Ni(NH3)42 in solution assumed to be at equilibrium? K, for [Ni(NH3)4] is 3.7 x 10¹6 O 5.4 x 10 M O 7.24x102M O 6.9 x 10¹M O 0.018 M

If 150 mL 0.0180 M Ni(NO3)2 and 125 mL of 0.25 M ammonia (NH₂) are diluted to 500 mL with deionized water. What is the concentrations of Ni(NH3)42 in solution assumed to be at equilibrium? K, for [Ni(NH3)4] is 3.7 x 10¹6 O 5.4 x 10 M O 7.24x102M O 6.9 x 10¹M O 0.018 M

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Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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If 150 mL 0.0180 M Ni(NO3)2 and 125 mL of 0.25 M ammonia (NH₂) are diluted to 500 mL with deionized water. What is the concentration of Ni(NH3)42 in solution assumed to be at equilibrium? K, for [Ni(NH3)42] is 3.7 x 10¹6 O 5.4 x 10 M O 7.24 x 102M O 6.9 x 10¹ M O 0.018 M.
Transcribed Image Text:If 150 mL 0.0180 M Ni(NO3)2 and 125 mL of 0.25 M ammonia (NH₂) are diluted to 500 mL with deionized water. What is the concentration of Ni(NH3)42 in solution assumed to be at equilibrium? K, for [Ni(NH3)42] is 3.7 x 10¹6 O 5.4 x 10 M O 7.24 x 102M O 6.9 x 10¹ M O 0.018 M.
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