Question 6: After research and observation the number of government system hackers active each day is a random variable with Bin(3, 0.5) distrobution. If no hackers are active the probabilty of a system failure is 0.15. If one hacker is active the probability of a system failure is 0.3. If two or more hackers are active the probabilty of a system failure is 0.5 (i) Conclude the total probability of a system failure on a given day. (Answer to 2 decimal places) Assuming there is a failure, what is the probabilty that no hackers are active.. (Answer to 2 decimal places) (ii)

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Chapter1: Combinatorial Analysis
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Question 6:
After research and observation the number of government system hackers active each day is a
random variable with Bin(3, 0.5) distrobution. If no hackers are active the probabilty of a system
failure is 0.15. If one hacker is active the probability of a system failure is 0.3. If two or more hackers
are active the probabilty of a system failure is 0.5
(i)
Conclude the total probability of a system failure on a given day. (Answer to 2 decimal
places)
Assuming there is a failure, what is the probabilty that no hackers are active.. (Answer
to 2 decimal places)
(ii)
Transcribed Image Text:Question 6: After research and observation the number of government system hackers active each day is a random variable with Bin(3, 0.5) distrobution. If no hackers are active the probabilty of a system failure is 0.15. If one hacker is active the probability of a system failure is 0.3. If two or more hackers are active the probabilty of a system failure is 0.5 (i) Conclude the total probability of a system failure on a given day. (Answer to 2 decimal places) Assuming there is a failure, what is the probabilty that no hackers are active.. (Answer to 2 decimal places) (ii)
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