Question 5 The following questions are based on hypothesis testing. (a) Let, (8.49, 10.39, 9.76, 12.66, 10.35, 10.96, 8.25, 12.14, 7.52, 8.92) * N (µ, o²) iid For the same dataset assume that the value of o² is also unknown. Again, at a = 0.01 or 1% significance level, test Họ : µ = 9 against H1 : µ # 9. Again calculate the test statistic, p-value and then comment on the null hypothesis.
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- Suppose that X, Y, and Z are jointly distributed random variables, that is, they are defined on the same sample space. Suppose that we also have the following. E(X)=-1 E(Y) = 4 E (Z)=0 Var(X)=20 Var(Y) = 27 Var (Z) = 38 Compute the values of the expressions below. E (5Z-2) = 0 2Z+X -5 Var(2X-3) = 0 E = E (32²) = 0 Explanation Check X O hp Ⓒ2022 McGraw Hill LLC. All Rights Reserved. TermThis Question: 4 pts 1 of 9 (0 complete) This Quiz: 45 pts possible Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: More than 54% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.1661. a. State a conclusion about the null hypothesis. (Reject H, or fail to reject Ho.) Choose the correct answer below. A. Reject Ho because the P-value is greater than a. B. Reject Ho because the P-value is less than or equal to a. C. Fail to reject H, because the P-value is less than or equal to a. O D. Fail to reject H, because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is…You wish to test the following claim (HaHa) at a significance level of α=0.01α=0.01. Ho:μ1=μ2Ho:μ1=μ2 Ha:μ1≠μ2Ha:μ1≠μ2You obtain the following two samples of data. Sample #1 Sample #2 65.8 77.7 105.1 78.6 89.2 69.1 96.7 91.3 105.9 87.5 70.5 93.9 83.4 88.3 79.5 66.7 83.4 91.7 106.7 73 75.7 98.7 76.7 80 53.2 92.1 93 78.2 72.4 79.1 82.1 74.1 78.2 85.5 85.9 99.3 84.2 104.3 88.3 107.6 63.8 99.8 97.7 86.3 74.9 72.7 77.5 93.9 76.1 77.1 81.9 74.1 73.6 78.7 81.9 78.9 81.1 88 85.8 75.3 74.3 77.5 69.1 75.5 72.9 80.1 84.3 73.1 67.3 72.2 76.1 67.8 74.9 67.3 74.7 70.1 65.4 76.9 83.8 79.7 72.9 81.7 74.1 68.2 65.4 80.9 69.4 79.5 96 77.5 77.1 75.9 68.7 What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? For this calculation, use the degrees of freedom reported from the technology you are using. (Report answer accurate to four…
- A high school conducts a dependent sample experiment to test if there is a difference between the number of times students are absent in the fall and winter months. You have data for the following 5 students: STUDENT FALL WINTER 1 2 3 4 5 2 0 1 2 O What do you conclude about this school's absences? (Assume standard a = 0.05) 2 1 2 4 T O There is no difference between the Fall and Winter months. O There is a statistically significant difference between the Fall and Winter months. There is a difference but it is only somewhat statistically significant. There is not enough data to determine if there is a difference in absences.You wish to test the following claim (HaHa) at a significance level of α=0.002α=0.002. Ho:μ1=μ2Ho:μ1=μ2 Ha:μ1<μ2Ha:μ1<μ2You obtain the following two samples of data. Sample #1 Sample #2 41.9 43.9 54.4 59.3 65.1 75.1 47.8 53.5 49.7 66.3 62.1 49.1 28.1 42.8 56.4 43.6 35.6 38.1 38.1 58.2 40.2 42.8 57.1 53.5 64 48.4 28.1 28.1 51.3 54.4 44.7 61.3 41.1 51.3 51.3 66.3 75.1 47.5 60.4 48.4 34.8 37.5 54.4 39.2 43.2 55.1 33.2 34 61.7 57.4 36.3 50.3 37.5 40.6 41.1 60.8 56.8 61.3 42.3 40.7 45.1 53.6 40 56.2 42.8 50.4 57.4 53.4 60.7 61 68.1 55.6 55.1 53.6 49.9 53.2 65.7 49.5 52.8 45.4 54.5 58.9 58.9 50.8 60.1 54.3 66.4 56.2 51.3 53.4 52.3 52.3 64.6 53.4 53.6 55.8 64.1 46.6 57.9 48 59.8 58.9 64.6 54.1 47.7 63.6 59.5 54.7 50.6 What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? For this calculation, use the…You wish to test the following claim (HaHa) at a significance level of α=0.001α=0.001. Ho:μ1=μ2Ho:μ1=μ2 Ha:μ1≠μ2Ha:μ1≠μ2You obtain the following two samples of data. Sample #1 Sample #2 50.8 84.4 72.1 78.4 72.9 48.8 87.4 36.1 78.8 51.7 74.7 56.3 65.2 98.6 72.5 72.1 72.9 54.2 69.8 73.4 51.7 68.5 59.4 86.8 48.8 47.6 48.8 85.6 65.2 43.4 76.1 69.8 43.4 69.4 55.6 74.3 108.9 92.4 77.9 46.4 47.6 93.3 60 72.9 74.7 66.6 72 84.3 66.1 75 86.5 96.6 47.1 79.1 75 74.5 82.2 77.8 79.5 70.9 71.5 104.8 88.8 81.7 99.8 89.3 91.2 87.9 111.1 66.1 68 79.5 82.6 61.4 90.7 115.1 106.9 60.4 50.1 85.7 61.4 100.5 105.8 79.1 88.3 73 68.6 57.1 70.9 67.4 42.4 52.3 80.4 88.8 What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? For this calculation, use the degrees of freedom reported from the technology you are using. (Report answer accurate to…
- Which of the following statements is true regarding the influence of a small alpha level in the context of hypothesis testing? a. A small alpha level reduces the likelihood of a Type I error. b. A small alpha level reduces the effect size. c. A small alpha level increases statistical power. d. A small alpha level increases the likelihood of detecting statistical significance.Looking at youth depression scores from a general sample of random children in the US, we want to determine if our sample is significantly different than the national average of scores of children with depression in the US. The national average of scores on a measure of depression is 5 points. We have no reason to assume it will be higher or lower than the US national average. The sample: 11 9 12 3 3 4 13 1. What is the null and alternative hypotheses? Do not specify any directionality. 2. What did you discover (using 95% Cl)? Provide an interpretation.Suppose that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 24%. Use a 0.10 significance level to test that claim. H: p>U.24 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Reject Ho- There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% O B. Fail to reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% OC. Fail to reject Hn. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 24% O D. Reject Ho. There is sufficient…
- Question #3 Samples of body temperatures were collected for a group of women and a group of men. The summary statistics are given below: Women:n1 = 15 sample mean = 98.38 ̊F s1 = 0.45 ̊F Men:n2= 91 sample mean= 98.17 ̊F s2 = 0.65 ̊F 1. Use a 0.01 significance level to test the claim that women and men have different mean body temperatures using the p value method. Show all the steps of your hypothesis test including the p value: initial conclusion: a final conclusion about the original claim:Question 4 く Test the claim that the mean GPA of night students is larger than the mean GPA of day students at the .01 significance level. The null and alternative hypothesis would be: Ho:PN = PD Ho:HN H1:PN > PD H1:µN > HD H1:PN < PD H1:PN # PD H1:µN < HD H1:µN # µD HD Ho:PN = PD Ho:PN = pD Ho:HN = HD Ho:UN = D The test is: two-tailed left-tailed right-tailed The sample consisted of 70 night students, with a sample mean GPA of 2.22 and a standard deviation of 0.03, and 50 day students, with a sample mean GPA of 2.21 and a standard deviation of 0.02. The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the nul hypothesisThe side effects of a new drug are being tested against a placebo. A simple random sample of 565 patients yields the results below. At a significance level of a 0:05, is there enough evidence to conclude that the treatment is independent of the side effect of nausea? Drug (c.1) 36 Placebo (c.2) Result Nausea (r.1) No nausea (r.2) Total Total 13 49 254 262 516 290 275 565 AI CAMON 11 16M AL Clear Selfie The END. Wishing you ALL the Best!