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Question 5 a. The plan in Figure Qu5a is for a footing subjected to a vertical load with two-way eccentricity. The footing is founded at a depth of 3 m below ground surface. The soil properties are: c =0 and unit weight = 18.5. If the bearing capacity factors are Ne = 46, Ng = 26.3 and Ny 26.55, determine: i. the ultimate bearing pressure due to this loading and ii. the load carrying capacity of the footing. %3D %3D 9429 2,773.5 e, 0.75 m 6 m x T. e, = 0.6 m 6 m

Question 5 a. The plan in Figure Qu5a is for a footing subjected to a vertical load with two-way eccentricity. The footing is founded at a depth of 3 m below ground surface. The soil properties are: c =0 and unit weight = 18.5. If the bearing capacity factors are Ne = 46, Ng = 26.3 and Ny 26.55, determine: i. the ultimate bearing pressure due to this loading and ii. the load carrying capacity of the footing. %3D %3D 9429 2,773.5 e, 0.75 m 6 m x T. e, = 0.6 m 6 m

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Additional details: Internal Angle of Friction = 33 degrees

Question 5 a. The plan in Figure Qu5a is for a footing subjected to a vertical load with two-way eccentricity. The footing is founded at a depth of 3 m below ground surface. The soil properties are: c = 0 and unit weight = 18.5. If the bearing capacity factors are Ne = 46, Ng = 26.3 and Ny = 26.55, determine: i. the ultimate bearing pressure due to this loading and ii. the load carrying capacity of the footing. %3! KNlan3 9429 3,773.5 e, = 0.75 m 6 m x e, = 0.6 m 6 m Figure Qu5a
Transcribed Image Text:Question 5 a. The plan in Figure Qu5a is for a footing subjected to a vertical load with two-way eccentricity. The footing is founded at a depth of 3 m below ground surface. The soil properties are: c = 0 and unit weight = 18.5. If the bearing capacity factors are Ne = 46, Ng = 26.3 and Ny = 26.55, determine: i. the ultimate bearing pressure due to this loading and ii. the load carrying capacity of the footing. %3! KNlan3 9429 3,773.5 e, = 0.75 m 6 m x e, = 0.6 m 6 m Figure Qu5a
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