What is the total angle of twist in radians for the following metal shaft? Answer to 4 decimal places [0.0000]. T = 1,544 lb-in, L = 1 ft, G = 9,290 ksi, J = 0.10 in^4 apguvor
What is the total angle of twist in radians for the following metal shaft? Answer to 4 decimal places [0.0000]. T = 1,544 lb-in, L = 1 ft, G = 9,290 ksi, J = 0.10 in^4 apguvor
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![**Problem Statement:**
What is the total angle of twist in radians for the following metal shaft? Answer to 4 decimal places [0.0000].
**Given:**
- Torque (T) = 1,544 lb-in
- Length (L) = 1 ft
- Shear Modulus (G) = 9,290 ksi
- Polar Moment of Inertia (J) = 0.10 in^4
**Solution:**
To solve this problem, we need to use the formula for the angle of twist (\(\theta\)) in a shaft:
\[
\theta = \frac{{T \cdot L}}{{G \cdot J}}
\]
Convert all units to the same system before calculating. Specifically, ensure that the length (L) is in inches because the polar moment of inertia (J) is given in inches to the fourth power:
Since \(1 \text{ ft} = 12 \text{ in}\),
\[
\theta = \frac{{1,544 \text{ lb-in} \times 12 \text{ in}}}{{9,290,000 \text{ psi} \times 0.10 \text{ in}^4}}
\]
Calculate \(\theta\) and round the result to four decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb1815343-0e1e-45bc-b31a-0935809f9211%2Fc57f8d51-8968-4e62-b468-0afca0e49f51%2F2npo3zo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
What is the total angle of twist in radians for the following metal shaft? Answer to 4 decimal places [0.0000].
**Given:**
- Torque (T) = 1,544 lb-in
- Length (L) = 1 ft
- Shear Modulus (G) = 9,290 ksi
- Polar Moment of Inertia (J) = 0.10 in^4
**Solution:**
To solve this problem, we need to use the formula for the angle of twist (\(\theta\)) in a shaft:
\[
\theta = \frac{{T \cdot L}}{{G \cdot J}}
\]
Convert all units to the same system before calculating. Specifically, ensure that the length (L) is in inches because the polar moment of inertia (J) is given in inches to the fourth power:
Since \(1 \text{ ft} = 12 \text{ in}\),
\[
\theta = \frac{{1,544 \text{ lb-in} \times 12 \text{ in}}}{{9,290,000 \text{ psi} \times 0.10 \text{ in}^4}}
\]
Calculate \(\theta\) and round the result to four decimal places.
Expert Solution

Step 1: Given data
Torque=T=1.544lb-in
length=L=1ft
ridigity=G=9290ksi
polar moment of inertia=J=
Step by step
Solved in 3 steps with 3 images

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