Need help with both questions **Question 4**What is the multiplicity of the methylene hydrogens indicated in the proton NMR of the following compound?![Chemical Structure](https://example.com/structure) -C6H5-CH2CH2CH2-C6H5-Options:- Pentet- Triplet- Quartet- Doublet---**Explanation of Diagram:**The image illustrates a chemical compound where two phenyl groups (C6H5) are connected by a propyl chain, specifically -CH2CH2CH2-. The arrow points to the middle methylene group (CH2) in the chain, indicating the hydrogens for which the NMR multiplicity needs to be determined. In the context of NMR spectroscopy, this multiplicity is influenced by the number of neighboring hydrogen atoms according to the n+1 rule. The question asks to determine the multiplicity of the central methylene hydrogens. **Question 3:**Which of the following structures is consistent with the IR spectra shown below?**Description of the IR Spectrum:**- The x-axis represents the wavenumber (cm⁻¹), ranging from about 4000 to 500 cm⁻¹.- The y-axis represents % Transmittance, ranging from 0% to 100%.- Notable peaks are observed at various points along the spectrum: - A broad trough around 3400 cm⁻¹, indicating the possible presence of an O-H group. - A distinct peak slightly above 3000 cm⁻¹, often associated with C-H stretching in aromatic or unsaturated compounds. - Multiple peaks between 1600 cm⁻¹ and 1450 cm⁻¹, typical for C=C stretching in aromatic rings. - Peaks below 1500 cm⁻¹, likely corresponding to fingerprint region characteristics (various functional groups and molecular structures).**Possible Structures:**The image shows five molecular structures on the left side, each associated with a different functional group. The task is to identify which structure matches the IR spectrum based on the peaks described.

“Since you have posted multiple questions, we will provide the solution only to the first question as per our Q&A guidelines. Please repost the remaining questions separately.” We have to find the number of neighboring proton which are responsible for splitting the proton into observation. Multiplicity = 2nI + 1 As we know for proton I= 1/2 So Multiplicity = n+1 Where n= neighboring proton So correct option is pentet