Question 4: Potential divider circuit illustrated below.R₁VAHow does Vв change when RL is;100 ΚΩ10 ΚΩ1 kn(i)(ii)R₂VBa) Show that VB = (R₂ / (R₁ + R₂)) x VAb) How does VB change when a load R₁ is attached?c) It is required to provide a 1 V source from a 10 V power supply VA, using a 1k2 and a 9k2 resistor.RL

Answered: Question 4: Potential divider circuit…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Step 1: Stating the given data

Given circuit:

$A s k e d space t o space f i n d space t h e comma space space space space a right parenthesis space S h o w space t h a t space V subscript B equals open parentheses fraction numerator R subscript 2 over denominator R subscript 1 plus R subscript 2 end fraction close parentheses cross times V subscript A space space space space b right parenthesis space W h a t space i s space t h e space c h a n h e space w h e n space R subscript L space i s space c o n n e c t e d space t o space t h e space c i r c u i t ? space space space space c right parenthesis space P r o v i d e space 1 space V space f r o m space 10 space V space s o u r c e comma space u s e space 1 space k capital omega space a n d space 9 space k capital omega space r e s i s t o r. space space space space space space space space T h e space c h a n g e space i n space V subscript B space end subscript space w h e n space R subscript L space i s space space space space space space space space space space space space space left parenthesis i right parenthesis space 100 space k capital omega space space space space space space space space space space space space space left parenthesis i i right parenthesis space 10 space k capital omega space space space space space space space space space space space space space left parenthesis i i i right parenthesis space 1 space k capital omega$

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