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Question 4: If you use the 1.8 g of carbon and 1.0 g of NażCr2O7 in a reaction, which of these will be the limiting reactant for Cr2O3? Question 5: What is the yield of the reaction if you produced 0.49 g of Cr203?

Question 4: If you use the 1.8 g of carbon and 1.0 g of NażCr2O7 in a reaction, which of these will be the limiting reactant for Cr2O3? Question 5: What is the yield of the reaction if you produced 0.49 g of Cr203?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question 4 and 5 please. Ensure that its clear. 

Use the following information for questions 1-7: South Africa has numerous natural resources. One of these is chromium which is mined in various areas across the country. While working in a lab you investigate the following reaction, with the goal of improving the extraction process: Na2Cr207(aq) + C(s) → Cr2O3(5) + N22CO3(aq) + CO(g) Question 1: You need 8.0 mole of Na2Cr207, how much would this weigh? Question 2: You have a look in the lab and find the carbon you need for the reaction. The bottle is nearly empty, and you only have 1.8 g. What mole amount is this? Question 3: Assuming you use the entire 1.8 g of carbon how much product, in grams, can you make of Cr2O3? Question 4: If you use the 1.8 g of carbon and 1.0 g of NażCr2O7 in a reaction, which of these will be the limiting reactant for Cr2O3? Question 5: What is the yield of the reaction if you produced 0.49 g of Cr2O3?
Transcribed Image Text:Use the following information for questions 1-7: South Africa has numerous natural resources. One of these is chromium which is mined in various areas across the country. While working in a lab you investigate the following reaction, with the goal of improving the extraction process: Na2Cr207(aq) + C(s) → Cr2O3(5) + N22CO3(aq) + CO(g) Question 1: You need 8.0 mole of Na2Cr207, how much would this weigh? Question 2: You have a look in the lab and find the carbon you need for the reaction. The bottle is nearly empty, and you only have 1.8 g. What mole amount is this? Question 3: Assuming you use the entire 1.8 g of carbon how much product, in grams, can you make of Cr2O3? Question 4: If you use the 1.8 g of carbon and 1.0 g of NażCr2O7 in a reaction, which of these will be the limiting reactant for Cr2O3? Question 5: What is the yield of the reaction if you produced 0.49 g of Cr2O3?
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