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QUESTION 4 For this problem, you will need to graph the data in Excel... so don't close this window! You will need to do an x-y scatter graph then do a linear regression in Excel. (if you don't know how to do this... email me or watch the lecture video!) If you were to determine kд by a multiple-point determination using the below Concetration and Signal data, then what would be the value of kA (the slope) that you got from your graph's linear regression? X-axis data (Concentration) Y-axis data (Signal) 3.12 x 103 M 18.72 6.33 x 103 M 41.18 8.22 x 10-3 M 56.73 1.02 x 10-2 M 61.22 1.39 x 102 M 89.31 What is the value of R? (Input your answer as a number without any units.) QUESTION 5 Using the value of kд that you got from QUESTION 3..... determine the concentration of your analyte solution (CA) if the signal obtained (SA) was 30.50. SA-KACA (Input your answer as a number without any units and in the format of 0.00XXX.)

QUESTION 4 For this problem, you will need to graph the data in Excel... so don't close this window! You will need to do an x-y scatter graph then do a linear regression in Excel. (if you don't know how to do this... email me or watch the lecture video!) If you were to determine kд by a multiple-point determination using the below Concetration and Signal data, then what would be the value of kA (the slope) that you got from your graph's linear regression? X-axis data (Concentration) Y-axis data (Signal) 3.12 x 103 M 18.72 6.33 x 103 M 41.18 8.22 x 10-3 M 56.73 1.02 x 10-2 M 61.22 1.39 x 102 M 89.31 What is the value of R? (Input your answer as a number without any units.) QUESTION 5 Using the value of kд that you got from QUESTION 3..... determine the concentration of your analyte solution (CA) if the signal obtained (SA) was 30.50. SA-KACA (Input your answer as a number without any units and in the format of 0.00XXX.)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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QUESTION 4 For this problem, you will need to graph the data in Excel... so don't close this window! You will need to do an x-y scatter graph then do a linear regression in Excel. (if you don't know how to do this... email me or watch the lecture video!) If you were to determine kд by a multiple-point determination using the below Concetration and Signal data, then what would be the value of kA (the slope) that you got from your graph's linear regression? X-axis data (Concentration) Y-axis data (Signal) 3.12 x 103 M 18.72 6.33 x 103 M 41.18 8.22 x 10-3 M 56.73 1.02 x 10-2 M 61.22 1.39 x 102 M 89.31 What is the value of R? (Input your answer as a number without any units.) QUESTION 5 Using the value of kд that you got from QUESTION 3..... determine the concentration of your analyte solution (CA) if the signal obtained (SA) was 30.50. SA-KACA (Input your answer as a number without any units and in the format of 0.00XXX.)
Transcribed Image Text:QUESTION 4 For this problem, you will need to graph the data in Excel... so don't close this window! You will need to do an x-y scatter graph then do a linear regression in Excel. (if you don't know how to do this... email me or watch the lecture video!) If you were to determine kд by a multiple-point determination using the below Concetration and Signal data, then what would be the value of kA (the slope) that you got from your graph's linear regression? X-axis data (Concentration) Y-axis data (Signal) 3.12 x 103 M 18.72 6.33 x 103 M 41.18 8.22 x 10-3 M 56.73 1.02 x 10-2 M 61.22 1.39 x 102 M 89.31 What is the value of R? (Input your answer as a number without any units.) QUESTION 5 Using the value of kд that you got from QUESTION 3..... determine the concentration of your analyte solution (CA) if the signal obtained (SA) was 30.50. SA-KACA (Input your answer as a number without any units and in the format of 0.00XXX.)
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