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(Q79) The first step of glycolysis (the metabolic conversion of glucose to pyruvate) is the addition of a phosphate group (P;) to glucose to form a compound known as glucose 6-phosphe (G6P) and release water. The balanced equation for this process is: Glucose + Pi --> G6P + H2O. Given that the standard Gibbs free energy for this process is +13 kJ/mol, what is the equilibrium constant (Kea) for this process when it takes place in the metabolism of an ordinary house cat (body temperature is 38.6°C)? O 6.64 x 103 -5.01 O 2.55 x 10-18 O 151 1.40

(Q79) The first step of glycolysis (the metabolic conversion of glucose to pyruvate) is the addition of a phosphate group (P;) to glucose to form a compound known as glucose 6-phosphe (G6P) and release water. The balanced equation for this process is: Glucose + Pi --> G6P + H2O. Given that the standard Gibbs free energy for this process is +13 kJ/mol, what is the equilibrium constant (Kea) for this process when it takes place in the metabolism of an ordinary house cat (body temperature is 38.6°C)? O 6.64 x 103 -5.01 O 2.55 x 10-18 O 151 1.40

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 83QRT: Another step in the metabolism of glucose, which occurs after the formation of glucose6-phosphate,...
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(Q79) The first step of glycolysis (the metabolic conversion of glucose to pyruvate) is the addition of a phosphate group (P;) to glucose to form a compound known as glucose 6-phosphe (G6P) and release water. The balanced equation for this process is: Glucose + P; --> G6P + H20. Given that the standard Gibbs free energy for this process is +13 kJ/mol, what is the equilibrium constant (Keg) for this process when it takes place in the metabolism of an ordinary house cat (body temperature is 38.6°C)? O 6.64 x 10-3 -5.01 O 2.55 x 10-18 151 O 1.40
Transcribed Image Text:(Q79) The first step of glycolysis (the metabolic conversion of glucose to pyruvate) is the addition of a phosphate group (P;) to glucose to form a compound known as glucose 6-phosphe (G6P) and release water. The balanced equation for this process is: Glucose + P; --> G6P + H20. Given that the standard Gibbs free energy for this process is +13 kJ/mol, what is the equilibrium constant (Keg) for this process when it takes place in the metabolism of an ordinary house cat (body temperature is 38.6°C)? O 6.64 x 10-3 -5.01 O 2.55 x 10-18 151 O 1.40
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