Question 4 A tow truck drags a stalled car along a road. The chain makes an angle 39 of with the road and the tension in the chain is 1300 N. How much work is done by the truck in pulling the car 9 km? Round your answer to the nearest whole number. A) 9,092,608 J B) 9,093 J C) 7,363,049 J D) 7,363 J 4,547 J
Question 4 A tow truck drags a stalled car along a road. The chain makes an angle 39 of with the road and the tension in the chain is 1300 N. How much work is done by the truck in pulling the car 9 km? Round your answer to the nearest whole number. A) 9,092,608 J B) 9,093 J C) 7,363,049 J D) 7,363 J 4,547 J
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Please just show work and answer want to compare my work thanks. No need to explain.
![### Work Done by a Tow Truck (Educational Example)
**Question 4 (4 points)**
A tow truck drags a stalled car along a road. The chain makes an angle of 39° with the road and the tension in the chain is 1300 N. How much work is done by the truck in pulling the car 9 km? Round your answer to the nearest whole number.
Options:
- **A)** 9,092,608 J
- **B)** 9,093 J
- **C)** 7,363,049 J
- **D)** 7,363 J
- **E)** 4,547 J
#### Explanation:
To solve for the work done, we apply the work formula that considers the angle between the force applied and the direction of motion:
\[ \text{Work} = F \cdot d \cdot \cos(\theta) \]
Where:
- \( F \) is the force applied (1300 N)
- \( d \) is the distance moved in the direction of the force (9 km or 9000 m)
- \( \theta \) is the angle between the force direction and the direction of motion (39°)
First, convert the distance from kilometers to meters:
\[ d = 9 \; \text{km} = 9000 \; \text{m} \]
Calculate the work done:
\[ \text{Work} = 1300 \; \text{N} \times 9000 \; \text{m} \times \cos(39°) \]
Using a calculator to find cosine of 39°:
\[ \cos(39°) \approx 0.7771 \]
Then plug in the values:
\[ \text{Work} \approx 1300 \times 9000 \times 0.7771 \]
\[ \text{Work} \approx 9,092,608 \; \text{J} \]
So, the correct answer is:
\[ \boxed{A) \; 9,092,608 \; \text{J}} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbbba0909-7b4f-4e80-8e24-06dfda2d061e%2Fa9b1ccbf-7962-4b5c-87ae-9eab3a5534de%2Fiwems3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Work Done by a Tow Truck (Educational Example)
**Question 4 (4 points)**
A tow truck drags a stalled car along a road. The chain makes an angle of 39° with the road and the tension in the chain is 1300 N. How much work is done by the truck in pulling the car 9 km? Round your answer to the nearest whole number.
Options:
- **A)** 9,092,608 J
- **B)** 9,093 J
- **C)** 7,363,049 J
- **D)** 7,363 J
- **E)** 4,547 J
#### Explanation:
To solve for the work done, we apply the work formula that considers the angle between the force applied and the direction of motion:
\[ \text{Work} = F \cdot d \cdot \cos(\theta) \]
Where:
- \( F \) is the force applied (1300 N)
- \( d \) is the distance moved in the direction of the force (9 km or 9000 m)
- \( \theta \) is the angle between the force direction and the direction of motion (39°)
First, convert the distance from kilometers to meters:
\[ d = 9 \; \text{km} = 9000 \; \text{m} \]
Calculate the work done:
\[ \text{Work} = 1300 \; \text{N} \times 9000 \; \text{m} \times \cos(39°) \]
Using a calculator to find cosine of 39°:
\[ \cos(39°) \approx 0.7771 \]
Then plug in the values:
\[ \text{Work} \approx 1300 \times 9000 \times 0.7771 \]
\[ \text{Work} \approx 9,092,608 \; \text{J} \]
So, the correct answer is:
\[ \boxed{A) \; 9,092,608 \; \text{J}} \]
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