Question 31 Suppose that Cr2O72-(aq) undergoes an oxidation-reduction reaction with Ru³+(aq) under acidic conditions and forms a species in which the ruthenium atom has an oxidation number of +7. Which of the following gives the balanced chemical equation for the reaction? show work. don't use Ai A. 6 Ru3+(aq) + Cr2O7²¯(aq) + 7 H₂O(/) - -> 6 Ru(OH)2+(aq) + 2 Cr³+(aq) + 2 OH-(aq) B. Ru3+(aq) + 2 Cr2O72-(aq) + 28 H+(aq) → Ru²+(aq) + 4 Cr³+(aq) + 14 H₂O(/) C. 2 Ru³+(aq) + 2 Cr2O7²¯(aq) + 14 H*(aq) → 2 RuO₂²+(aq) + 4 Cr³+ (aq) + 7 H₂O(1) D. 3 Ru³+(aq) + 2 Cr2O7²¯(aq) + 4 H+(aq) → 3 RuO4˜¯(aq) + 4 Cr³+(aq) + 2 H2O(1)
Question 31 Suppose that Cr2O72-(aq) undergoes an oxidation-reduction reaction with Ru³+(aq) under acidic conditions and forms a species in which the ruthenium atom has an oxidation number of +7. Which of the following gives the balanced chemical equation for the reaction? show work. don't use Ai A. 6 Ru3+(aq) + Cr2O7²¯(aq) + 7 H₂O(/) - -> 6 Ru(OH)2+(aq) + 2 Cr³+(aq) + 2 OH-(aq) B. Ru3+(aq) + 2 Cr2O72-(aq) + 28 H+(aq) → Ru²+(aq) + 4 Cr³+(aq) + 14 H₂O(/) C. 2 Ru³+(aq) + 2 Cr2O7²¯(aq) + 14 H*(aq) → 2 RuO₂²+(aq) + 4 Cr³+ (aq) + 7 H₂O(1) D. 3 Ru³+(aq) + 2 Cr2O7²¯(aq) + 4 H+(aq) → 3 RuO4˜¯(aq) + 4 Cr³+(aq) + 2 H2O(1)
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter20: Chemistry Of The Metals
Section: Chapter Questions
Problem 38QAP
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Transcribed Image Text:Question 31
Suppose that Cr2O72-(aq) undergoes an oxidation-reduction reaction with Ru³+(aq) under acidic conditions
and forms a species in which the ruthenium atom has an oxidation number of +7. Which of the following
gives the balanced chemical equation for the reaction?
show work. don't
use Ai
A. 6 Ru3+(aq) + Cr2O7²¯(aq) + 7 H₂O(/) -
-> 6 Ru(OH)2+(aq) + 2 Cr³+(aq) + 2 OH-(aq)
B. Ru3+(aq) + 2 Cr2O72-(aq) + 28 H+(aq) → Ru²+(aq) + 4 Cr³+(aq) + 14 H₂O(/)
C. 2 Ru³+(aq) + 2 Cr2O7²¯(aq) + 14 H*(aq) → 2 RuO₂²+(aq) + 4 Cr³+ (aq) + 7 H₂O(1)
D. 3 Ru³+(aq) + 2 Cr2O7²¯(aq) + 4 H+(aq) → 3 RuO4˜¯(aq) + 4 Cr³+(aq) + 2 H2O(1)
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