Question.3.1 A circular curve is used as part of the horizontal alignment of a 2-lane, one wayroad. The curve has central angle (A) = 83° 7' 28.8", PI chainage = 0+905.280 and BCchainage =0 +639.280. Calculate the following:3.1.1 The curve radius, curve length and EC chainage.3.1.2 The deflection angle at chainage 1+040.0003.1.3 The curve total widening requirement if the design vehicle is articulated bus.3.2 A horizontal curve is used in a 2-lane, two-way rural road. The design speed is100 km/h and curve radius is 700 m. Calculate the required superelevation rate. Also,provide a comment on the result (Hint: Consult TRH17 and estimate the value forlateral coefficient of friction).3.3 For the horizontal curve in Q 3.2, determine the curve radius if the maximumsuperelevation is 8% and free-steering condition is considered.

*Multiple questions* As per our guidelines we are supposed to answer?️ only one question. Kindly…

Question 3.1 A circular curve is used as part of the horizontal alignment of a 2-lane, one way road. The curve has central angle (A) = 83° 7' 28.8", PI chainage = 0+905.280 and BC chainage =0 +639.280. Calculate the following: 3.1.1 The curve radius, curve length and EC chainage. 3.1.2 The deflection angle at chainage 1+040.000 3.1.3 The curve total widening requirement if the design vehicle is articulated bus.

Question 3.1 A circular curve is used as part of the horizontal alignment of a 2-lane, one way road. The curve has central angle (A) = 83° 7' 28.8", PI chainage = 0+905.280 and BC chainage =0 +639.280. Calculate the following: 3.1.1 The curve radius, curve length and EC chainage. 3.1.2 The deflection angle at chainage 1+040.000 3.1.3 The curve total widening requirement if the design vehicle is articulated bus.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Two tangents intersect at a chainage 50.60 (50 chains + 60 links). The deflection angle being 61°.…

A: Given data:Chainage of point of Intersection (PI) = 50.60 chains PI= 50.60× 20 = 1012 m Deflection…

Q: Q.37 An ascending gradient of 1 in 100 meets a descending gradient of 1 in 120. A summit curve is to…

A: Ascending gradient(n1) = 1/100Descending gradient ( n2 )= - 1/120Design speed = 100kmph =…

Q: Use the simplified version of the basic curve equation to calculate the minimum radius (m) for a…

Q: 6. The following figure shows a two-lane road with curve 1 having a horizontal curve length of…

A: Overlap length ≈ 621.16 ftSo, the curves would overlap by approximately 621.16 ft under standard…

Q: ẩj a simplẩe ẩjlar curve with the following properties: D= 11°, intersection angle A= 30.375, and…

Q: slope. It has a side slope of 2:1 and the base width of the roadway is 12 m. (a) Compute the volume…

A: Side slope = 2:1 Base width = 12 m For station 10+110, Cross section…

Q: Q2) Given the degree of curve for the figure below is 5°, central angle is 72°30' and the point of…

A: As per Bartleby guidelines, I have solved first 3 sub parts of a single question. If you need…

Q: Determine variables requested below for a horizontal curve with the following characteristics.…

A: We have to determine the value of tangent of the given horizontal curve as per the given data in the…

Q: The length of the spiral curve is 80 m. with a radius of 280 m. (a) Determine the offset distance…

Q: A road 14.4 m wide is to deflect through an angle of 48° with the center line radius of 300 m, the…

A: Transition curve: A transition curve is defined as a curve with a varying radius. The transition…

Q: s the following data: Azimuth of back tangent = 205° Azimuth of forward tangent = 262° Middle…

Q: Problem No. 2: A compound curve has a central angle of 40deg. and radius 280m. The second curve has…

Q: A simple curve has a back tangent with an azimuth of 200° from PC. The forward tangent has an…

Q: A simple circular curve has a radius of 300 m and 60° deflection angle. Compute the following: a.…

A: Given, Radius of the curve= R= 300m, Deflection angle= ∆= 60° Note :- as per our company…

Q: If a compound curve has a following data. Il = 28°, 12 =38°, R1 = 380m, R2 = 220m, and P.C is at…

Concept explainers

Graphical Methods

The graphical method is a method of solving equations involving more than one variable using the Cartesian coordinate system. In civil engineering, the use of the graphical method is limited to the problems involving two variables. The graphical method has a great impact in solving the questions regarding engineering mechanics.

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

QUESTION 9 Use the simplified version of the basic curve equation to calculate the minimum radius (ft) for a horizontal curve given a design speed of 60 mph, a maximum superelevation of 6.0% and maximum friction factor of 0.12 QUESTION 10 A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the PC is at station 3 + 65.00 ft, what is the last deflection angle (degrees) (i.e. the angle subtended by the roadway between the last full station and the PT)?
DETERMINE THE FOLLOWING FIGURE OF A SIMPLE CURVE 1. DEGREE OF CURVE, LENGTH OF T, LC and angle B 21.35 73.74 V2-3687 36.87 LC R215m
Use the simplified version of the basic curve equation to calculate the minimum radius (ft) for a horizontal curve given a design speed of 60 mph, a maximum superelevation of 6.0% and a maximum friction factor of 0.12.
Example 15.7 Design of a Compound Curve Figure 15.23 illustrates a compound curve that is to be set out at a highway intersec- tion. If the point of compound curve (PCC) is located at station (565 + 10.5), deter- mine the deflection angles for setting out the curve. 60° 26 340 PCC PC 26° PT R-150 m 34 R, 105 m Figure 15.23 Compound Curve for Example 15.7
3 Horizontal curves You are asked to design a 5-degree horizontal curve with an intersection angle at the center equals 60°15'. The station of point of curvature is 155 + 26.5 ft. Calculate the following: A. Length of the curve B. Station of the point of tangency (PT) C. For first two whole stations next to PC, calculate the degree of deflection from the PC and chord length from the previous point along the horizontal curve.
Answer g and h please
Correct answer urgent...m