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a) The radius (R) b) The tangent length (T) c) The external distance (E) d) The middle ordinate (M) e) The long cord (C). Use equation 15.23, p. 805. f) The length of the curve (L) g) Station of PC h) Station of PT

a) The radius (R) b) The tangent length (T) c) The external distance (E) d) The middle ordinate (M) e) The long cord (C). Use equation 15.23, p. 805. f) The length of the curve (L) g) Station of PC h) Station of PT

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Answer g and h please
The expression for the length C of the chord AB, which is known as the long chord, is C = 2R sin (15.23) s noitooliob tzon of 1
Transcribed Image Text:The expression for the length C of the chord AB, which is known as the long chord, is C = 2R sin (15.23) s noitooliob tzon of 1
Given a simple circular curve with the following properties: D = 11°, intersection angle A= 30.375, and the station of the PI = 22+69.77. Determine the following: a) The radius (R) b) The tangent length (T) c) The external distance (E) d) The middle ordinate (M) e) The long cord (C). Use equation 15.23, p. 805. f) The length of the curve (L) g) Station of PC h) Station of PT
Transcribed Image Text:Given a simple circular curve with the following properties: D = 11°, intersection angle A= 30.375, and the station of the PI = 22+69.77. Determine the following: a) The radius (R) b) The tangent length (T) c) The external distance (E) d) The middle ordinate (M) e) The long cord (C). Use equation 15.23, p. 805. f) The length of the curve (L) g) Station of PC h) Station of PT
Expert Solution
Step 1

Given:

The intersection angle is, ∆=30.375

The station of the PI is, PI=22+69.77

 

 

 

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