Question 3: The motor exerts a force of F = 20 t² N on the cable, where t is in seconds. Determine the speed of the 25 kg crate when t = 4 s. The coefficient kinetic friction between the crate and the plane is u = 0.25. %3D

Question 3: The motor exerts a force of F = 20 t² N on the cable, where t is in seconds. Determine the speed of the 25 kg crate when t = 4 s. The coefficient kinetic friction between the crate and the plane is u = 0.25. %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: system that has characteristics of a spring with a constant 45 lbs / ft. If the car has an initial…

A: In the question, the friction is given to be zero. Thus there will no loss of energy possessed by…

Q: determine the velocity of the 25-kg crate when t = 4 s.

Q: 3) The log has a mass of 500 kg and rests on the ground for which the coefficients of static and…

Q: The free-body diagram for the slider is shown. Solve for the forces N and F. F N mg Answers: F = i…

A: As per bartleby guidelines we are allowed to solve only 1st question if multiple questions are…

Q: Block B rests upon a smooth surface. If the coefficients of static and kinetic friction between A…

Q: 2. A 40 kg block is at rest on the slope when a force F is applied to it. Determine the magnitude of…

A: Mass of block = 40kg Find the force F is the velocity is 5m/s at t=2sec

Q: Determine the largest force P (to the nearest integer) which can be applied to the cord without…

Q: The force F, acting in a constant direction on the 19-kg block, has a magnitude which varies with…

Q: Block A has a mass of 20 kg and B 5 kg . Th coefficient of friction between all surfaces of contact…

Q: Determine the velocity of the block A in (m/s) with a mass of 42 kg if the two blocks are released…

A: According to the given data initially at rest Mass mA= 42 kgmass mB=18 kgSB=0.6mμk=0.10g=9.81 m/s2…

Q: The 50-kg crate is pulled by the constant force P. If the crate P starts from rest and achieves a…

Q: Determine the largest acceleration of the truck so that the safe will not slip or tip on the truck…

Q: The box is at rest at point 1 when it is sliding down the incline. If the 1 1 H, = 0.40 HA = 0.30…

A: Let mass of box be M After beginning of motion kinetic friction comes into action So from 1 to 2 FBD…

Q: Q1. The slender 15 kg bar is initially at rest and standing in the vertical position when the bottom…

A: The data given is,Initial velocity, v1 = 0mass of slender, m = 15 kgTo determine:The speed at which…

Q: The 103-lb crate is carefully placed with zero velocity on the incline. What is the acceleration of…

A: A crate placed on an inclined plane m=103lb

Q: Q1:The system is initially at rest with no slack in the cable, and the mass and friction of the…

Q: Determine the force P needed to (a) impend the crate to slide up the 15° -incline plane (b) give the…

A: Given data:

Q: The 40-lb crate slides down the curved path in the vertical plane. If the crate has a velocity of…

A: GivenW=40 lb=4032.2=1.24kgvA=3.7 m/s2vB=27.6 ft/s

Q: A 25 - lb block-on-a-slope (0 = 30°) mechanism has been arranged in the Dynamics lab so that at the…

Q: If the 40kg box is moving with 1 m/s^2 acceleration to the right, determine the magnitude of normal…

A: Mass of box, m=40kg Acceleration of box, a=1 m/s2 Force, F=174N Kinetic friction, μ=0.3

Q: The force F, acting in a constant direction on the 24-kg block, has a magnitude which varies with…

A: The mass of the block is m=24 kg. The coefficient of kinetic friction is μk=0.3. The initial…

Q: The system is released from rest with the spring initially stretched 4.8 in. Calculate the velocity…

A: The spring stretched length of spring l=4.8 in The spring stiffness is given as, k=5.2 lb/in The…

Q: The 40-lb crate slides down the curved path in the vertical plane. If the crate has a velocity of…

A: Given- Weight (W) = 40 lb Initial velocity (VA) = 3.7 ft/sec Height at position A = (h) = 19 ft…

Q: The 50-lb block rests on the rough surface for which the coefficient of kinetic friction is 14k =…

A: Given data:

Q: determine the acceleration of each block.

Q: a 7.4 lb block has a speed of v-2.4 ft/s to the left when the force of F=3.6t^3 lb is applied to the…

A: Given: The weight of block, m = 7.4 lb The speed of block, v = 2.4 ft/s The force acting, F = 3.6t^3…

Q: Q4:- If the coefficient of kinetic friction between the 50 kg crate and the ground is µ = 0.3,…

Q: The system is released from rest with the spring initially stretched 2.4 in. Calculate the velocity…

Q: The snowmobile has a weight of 250-lb, centered at G1, while the rider has a weight of 145-lb at G2.…

Q: 1. If I want the 100-lb block to move with a constant acceleration of 5 ft/s² up the slope, what is…

Q: The 50-lb crate is subjected to the force F = 40 lb. The coefficient of kinetic friction between the…

Q: 1) If the 50-kg crate is subjected to a force of P = 200 (N), determine its speed when it has…

A: In this question I have solved using both the methods to get the solution in different ways.…

Q: he 10-lb block has a speed of 4 ft/s when the force of F=(8t2) lb is applied. The coefficient of…

A: Given data as per the question Mass of block =10 lb speed of block =4 ft/s coefficient of friction…

Q: = 14 ft/s to 14.102 The 1-lb block is given an initial velocity vo the right when it is in the…

A: Initial velocity = 14 ft/s

Q: If the motor exerts a force of F determine the speed of the 21.7-kg crate when it travels s = 9.56 m…

A: Mechanical Equilibrium: A body is said to be in mechanical equilibrium if it satisfies the following…

Q: 2. The block (A) has a mass of 10 kg and the coefficient of dynamic friction between the block and…

A: “Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: 2-) After releasing the system shown below from rest, determine the total displacemen the block on…

A: The coefficient of friction is

Q: 0.3. Initially, the crate is at the position The coefficient of kinetic friction between the m =…

A: Given data mass of the crate (m) = 10.4 kg coefficient of friction () = 0.3 Intial velocity (v1) =…

Q: Block A has a mass of 10 kg and bloc B has a mass of 2 Kg and are kept at rest. The 2 blocs are…

A: Given, mass of block A , ma = 10 kg. mass of block B , mb = 2 kg coefficient of friction , k =…

Q: Am = 12 kg particle is moving along a horizontal path defined by the equations r= (4.5.t+13) m and =…

Concept explainers

Forming and Shaping

Metal forming is a category of metalworking process through which the material can be given the desired shape and size by subjecting it to plastic deformation, where the component undergoes bulk deformation process upon application of loads. Unlike the shearing and machining process, the material does not undergo up to a failure point as indicated in the stress-strain curve. Hence, the stresses induced during the forming process are greater than yield strength but less than the failure strength of the material. The process does not lead to the loss of material, so it can be said to be an economical process. During forming, the material is subjected to tensile forces, compressive forces, bending, and shearing loading conditions. The material should possess the property of ductility to undergo the forming process.

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

The 210-kg crate rests on the ground for which the coefficients of static and kinetic friction are us = 0.5 and ui = 0.4, respectively. The winch delivers a horizontal towing force T to its cable at A which varies as shown in the graph. Originally the tension in the Part A cable is zero. (Figure 1) Determine the speed of the crate when t = 3.8 s. Hint: First determine the force needed to begin moving the crate. Express your answer to three significant figures and include the appropriate units. > View Available Hint(s) HA v = Value Units Submit Figure Provide Feedback T (N) 800 T= 400 1/2 t (s)
Pls. specify the procedure
A small boat carrying people with a total weight of 362 Ibs slide down the incline whose dimensions are h=112 ft and d=117 ft. The coefficient of kinetic friction between the boat and the slide is 0.14. Determine the time it takes the boat to go from A to B, use 3 decimals for your answer. The boat starts sliding at A from rest. A d
Q14. As shown in the image below, the 20-kg box is pulled up the inclined plane with a constant velocity of 4.7 m/s. If the coefficient of kinetic friction between the box and the inclined plane is µ = 0.1, determine the power of force F. Please pay attention: the numbers may change since they are randomized. Your answer must include 1 place after the decimal point, and proper SI unit. Take g = 9.81 m/s². F Your Answer: Answer 30° units
If the coefficient of kinetic friction between the150-lb crate and the ground is uk = 0.2, %3D determine the speed of the crate when t = 4 s. The crate starts from rest and is towed by %3D the 100-lb force. 100 lb 30°
At the start, Box A has a speed of 3 m/s upward the inclined plane with a kinetic friction equal to 0.15. Determine the speed of Box B at t = 6 seconds.
The truck is traveling at 18 km/h when the trailer coupling at A fails. If the trailer has a mass of 255 kg and it travels a distance of 40 m before coming to a stop, determine the constant horizontal force F created by bearing friction that causes the trailer to stop (in N). NL (O) == O F
Question: The 250-kg crate rests on the ground for which the coefficients of static and kinetic friction are μs = 0.5 and μk = 0.4, respectively. The winch delivers a horizontal towing force T to its cable at A which varies as shown in the graph. Originally the tension in the cable is zero Part A) Determine the speed of the crate when t = 3.9 s. Hint: First determine the force needed to begin moving the crate. Express your answer to three significant figures and include the appropriate units.
The 200-lb man walks up the inclined plank of negligible weight. Thecoefficients of static friction at A and B are 0.3 and 0.2, respectively.Determine the distance x at which the plank would begin to slide.
The 10 kg block is subject to the action of a force that has the constant direction towards the spring, with a magnitude F= 250 (1 + x) N, where x is measured in meters. If the coefficient of kinetic friction between the block and the horizontal surface is 0.20, and ks= 50 N/m Use the springs por your calculations Determine: a) The work done by all the forces acting on the block during a movement from A to B. b) If the block starts from rest at point A, determine its velocity at point B using the equation of motion (Newton's 2nd Law). c) Verify the speed obtained in b) through the equation of work and Kinetic Energy. d) Explain the differences between the two methods used to find the velocity, from the point of view of the volume of calculations. Recomendations: 1. No force (except weight) is constant throughout travel 2. Acceleration is not constant at any point along the way. 3. When applying Newton's second law, it is advisable to do it in two sections. 4. Review the…
The homogeneous cylinder A has a mass of 80 kg, and the mss of the hub can be neglected. The magnitude of the variable force P, is in newtons when t is in sec- onds. The velocity of body B changes from 2 m/s downward when t = 0 to 4 m/s downward t = 5 s. Determine the mass of B. Solve all questions using Impulse and Momentum methods
A constant force of ''F'' acts on a mass as shown. The mass starts its motion from rest at position 1, the unstretched length of the spring is 250 mm, and the spring modulus is k=1,5 k?/m. Neglecting the friction, determine the required force ''F'' to cause the 2−kg mass to have a speed of v2=1,5 m/s at position 2.