Question #3 The following forces act at appoint: 30 N in the direction 20° south of east 20 N in the direction due north 10 N in the direction south-west 16 N in the direction 50 south of west Find the magnitude and direction of the resultant force.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Question #3
The following forces act at appoint:
30 N in the direction 20° south of east
20 N in the direction due north
10 N in the direction south-west
16 N in the direction 5⁰ south of west
Find the magnitude and direction of the resultant force.
Transcribed Image Text:Question #3 The following forces act at appoint: 30 N in the direction 20° south of east 20 N in the direction due north 10 N in the direction south-west 16 N in the direction 5⁰ south of west Find the magnitude and direction of the resultant force.
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Kindly advise where i went wrong, i am not getting back your answer 

Calculation of the forces in x-direction
Efx = 30 cos 20° - 10 cos 45º - 16 cos 5°
= 5.18 N
calculation of the forces in y-direction
Σfy = - 30sin 20 - 10 SÅN 45 -16 sin 5 + 20
= 1.27 N
Magnitude = √√(IE₂)² + (ZF₂)²
√(5·18)²+(1.2792
=
= 5.33 N
Direction=
tan' ('[ Fy
IFx
= tan" (1:777)
5.18
13.77
WF
1611
ION
5
45
AZON
20*
SON
E
Transcribed Image Text:Calculation of the forces in x-direction Efx = 30 cos 20° - 10 cos 45º - 16 cos 5° = 5.18 N calculation of the forces in y-direction Σfy = - 30sin 20 - 10 SÅN 45 -16 sin 5 + 20 = 1.27 N Magnitude = √√(IE₂)² + (ZF₂)² √(5·18)²+(1.2792 = = 5.33 N Direction= tan' ('[ Fy IFx = tan" (1:777) 5.18 13.77 WF 1611 ION 5 45 AZON 20* SON E
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Follow-up Question

I am not getting the answer kindly advise where I went wrong 

Calculation of the forces in x-direction
Efx = 30 cos 20° - 10 cos 45º - 16 cos 5°
= 5.18 N
calculation of the forces in y-direction
Σfy = - 30sin 20 - 10 SÅN 45 -16 sin 5 + 20
= 1.27 N
Magnitude = √√(IE₂)² + (ZF₂)²
√(5·18)²+(1.2792
=
= 5.33 N
Direction=
tan' ('[ Fy
IFx
= tan" (1:777)
5.18
13.77
WF
1611
ION
5
45
AZON
20*
SON
E
Transcribed Image Text:Calculation of the forces in x-direction Efx = 30 cos 20° - 10 cos 45º - 16 cos 5° = 5.18 N calculation of the forces in y-direction Σfy = - 30sin 20 - 10 SÅN 45 -16 sin 5 + 20 = 1.27 N Magnitude = √√(IE₂)² + (ZF₂)² √(5·18)²+(1.2792 = = 5.33 N Direction= tan' ('[ Fy IFx = tan" (1:777) 5.18 13.77 WF 1611 ION 5 45 AZON 20* SON E
Solution
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