Hw question 3 0.456 atmQUESTION 3Determine the equilibrium constant, Keg, at 25°C for the reaction2Br (aq) +12(s) = Br 2(0) + 21- (aq).18.3001.7 x 105419 x 1018O 5.7 x 10-1957x 10-55Cliek Save and Submit to save and submit. Chek Save All Answers to save1-4nswers to saue

The given reaction is, 2 Br-(aq) + I2(s) ⇔ Br2(l) + 2 I-(aq)

Answered: QUESTION 3 Determine the equilibrium…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Hw question 3

Expert Solution

Step 1

The given reaction is,

${2 Br}^{-}_{(aq)} {+ I}_{2 (s)} \Leftrightarrow {Br}_{2 (l)} {+ 2 I}^{-}_{(aq)}$

Step 2

We have the relation,

${n×F×E°}_{cell} = R×T×ln K n = 2 electrons F = 96500 R = 8.314 T = 298 \ln K = \frac{{n×F×E°}_{cell}}{R×T}$

Step 3

${E^{o}}_{(cell)} {= E}^{o}_{reduction} {- E}^{o}_{oxidation} {E^{o}}_{(cell)} {= E}^{o}_{I_{2 / I^{-}}} {- E}^{o}_{{Br}^{-} {/Br}_{2}} {Br}_{2 (l)} + 2 e^{-} \to 2 {Br}^{-}_{(aq)} = 1.07 v I_{2 (s)} + 2 e^{-} \to 2 {I^{-}}_{(aq)} = 0.54 v {E^{o}}_{(cell)} = 0.54 - 1.07 {E^{o}}_{(cell)} = - 0.53 v$

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