Question 3 Calculate the amount of heat absorbed by 10.0 grams of ice at-15.0°C as it is converted to liquid water at 50.0°C. The specific heat of H20(s) = 2.09 J/(g°C). The %3D specific heat of H20(1) = 4.18 J/(g°C). The heat of fusion is 333 J/g. O 0.676kJ O 0.170kJ O 5.73kJ O 2.83kJ Next

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Question 3
Calculate the amount of heat absorbed by 10.0 grams of ice at -15.0°C as it is
Evaporating th
%3D
converted to liquid water at 50.0°C. The specific heat of H20(s) = 2.09 J/(g°C). The
physics
1. a) using
specific heat of H20(1) = 4.18 J/(g°C). The heat of fusion is 333 J/g.
conservatic
determine
of fusion
percenta
determir
0.676KJ
-0.1kg
-56 C
Che
How
O 0.170kJ
con
155
he
5.73kJ
O 2.83kJ
Next
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Transcribed Image Text:Question 3 Calculate the amount of heat absorbed by 10.0 grams of ice at -15.0°C as it is Evaporating th %3D converted to liquid water at 50.0°C. The specific heat of H20(s) = 2.09 J/(g°C). The physics 1. a) using specific heat of H20(1) = 4.18 J/(g°C). The heat of fusion is 333 J/g. conservatic determine of fusion percenta determir 0.676KJ -0.1kg -56 C Che How O 0.170kJ con 155 he 5.73kJ O 2.83kJ Next Previous
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