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Question #3 A resistor, denoted as R,, is added in series with the inductor in the circuit in Fig. 14.4(a). The new low- pass filter circuit is shown in Fig. P14.3. a) Derive the expression for H(s) where H(s) = V₁/V;- b) At what frequency will the magnitude of H(jw) be maximum? c) What is the maximum value of the magnitude of H(jw)? d) At what frequency will the magnitude of H(jw) equal its maximum value divided by V2? e) Assume a resistance of 300 is added in series with the 50 mH inductor in the circuit in Fig. P14.1. Find of, H(0), H(jor), H(j0.2m,), and (5) Solution #6 (R/L) ++ (144) (R/L) [b][j]- (N/5) ( ocens when - My R R BIL W = (R+R)/L 1200 300 eX 30,000 rad/s 0.05 113) 24,000 H-08 K 30,000) 45° = 0.5651/- 45° v2 24,000 6000)- -0.3845/-11.31" 24,000 H150.000)- -0.1560-78.07 R

Question #3 A resistor, denoted as R,, is added in series with the inductor in the circuit in Fig. 14.4(a). The new low- pass filter circuit is shown in Fig. P14.3. a) Derive the expression for H(s) where H(s) = V₁/V;- b) At what frequency will the magnitude of H(jw) be maximum? c) What is the maximum value of the magnitude of H(jw)? d) At what frequency will the magnitude of H(jw) equal its maximum value divided by V2? e) Assume a resistance of 300 is added in series with the 50 mH inductor in the circuit in Fig. P14.1. Find of, H(0), H(jor), H(j0.2m,), and (5) Solution #6 (R/L) ++ (144) (R/L) [b][j]- (N/5) ( ocens when - My R R BIL W = (R+R)/L 1200 300 eX 30,000 rad/s 0.05 113) 24,000 H-08 K 30,000) 45° = 0.5651/- 45° v2 24,000 6000)- -0.3845/-11.31" 24,000 H150.000)- -0.1560-78.07 R

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question #3 A resistor, denoted as R,, is added in series with the inductor in the circuit in Fig. 14.4(a). The new low- pass filter circuit is shown in Fig. P14.3. a) Derive the expression for H(s) where H(s) = V₁/V;- b) At what frequency will the magnitude of H(jw) be maximum? c) What is the maximum value of the magnitude of H(jw)? d) At what frequency will the magnitude of H(jw) equal its maximum value divided by V2? e) Assume a resistance of 300 is added in series with the 50 mH inductor in the circuit in Fig. P14.1. Find of, H(0), H(jor), H(j0.2m,), and (5) Solution #6 (R/L) ++ (144) (R/L) [b][j]- (N/5) ( ocens when - My R R BIL W = (R+R)/L 1200 300 eX 30,000 rad/s 0.05 113) 24,000 H-08 K 30,000) 45° = 0.5651/- 45° v2 24,000 6000)- -0.3845/-11.31" 24,000 H150.000)- -0.1560-78.07 R
Transcribed Image Text:Question #3 A resistor, denoted as R,, is added in series with the inductor in the circuit in Fig. 14.4(a). The new low- pass filter circuit is shown in Fig. P14.3. a) Derive the expression for H(s) where H(s) = V₁/V;- b) At what frequency will the magnitude of H(jw) be maximum? c) What is the maximum value of the magnitude of H(jw)? d) At what frequency will the magnitude of H(jw) equal its maximum value divided by V2? e) Assume a resistance of 300 is added in series with the 50 mH inductor in the circuit in Fig. P14.1. Find of, H(0), H(jor), H(j0.2m,), and (5) Solution #6 (R/L) ++ (144) (R/L) [b][j]- (N/5) ( ocens when - My R R BIL W = (R+R)/L 1200 300 eX 30,000 rad/s 0.05 113) 24,000 H-08 K 30,000) 45° = 0.5651/- 45° v2 24,000 6000)- -0.3845/-11.31" 24,000 H150.000)- -0.1560-78.07 R
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