Question 29Naphthalene, C10H8, melts at 80.2 °C. If the vapor pressure of the liquid is 1.3 kPa at 85 °C and 5.3 kPa at 119.3 °C, use theClausius-Clapeyron equation to calculate the normal boiling point.OA.47.8 KB. 48.0 KOc. 610 KD. 600 KO E. 78.4 Kda) ENG

Determination of normal boiling point of naphthalene using clausius clapeyron equation

Question 29 Naphthalene, C10H8, melts at 80.2 °C. If the vapor pressure of the liquid is 1.3 kPa at 85 °C and 5.3 kPa at 119.3 °C, use Clausius-Clapeyron equation to calculate the normal boiling point. OA. 47.8 K OB. 48.0 K OC. 610 K O D. 600 K OE. 78.4 K

Question 29 Naphthalene, C10H8, melts at 80.2 °C. If the vapor pressure of the liquid is 1.3 kPa at 85 °C and 5.3 kPa at 119.3 °C, use Clausius-Clapeyron equation to calculate the normal boiling point. OA. 47.8 K OB. 48.0 K OC. 610 K O D. 600 K OE. 78.4 K

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Solids are present all around us. They have different properties and applications. Diamond and graphite are two well-known solids. Diamond is the hardest material in the world and is used in making jewelry. Graphite on the other hand is soft. The lead of your pencil is graphite. Why are they so different in appearance and properties despite the fact they are chemically the same? Both are allotropes of carbon. The answer lies in the structure, the way constituent particles are arranged in the solids.

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