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QUESTION 25 In this class we will limit our study of free radical halogenation to free radical chlorination and free radical bromination. Bromine is a larger, "slower and fussier" atom than chlorine, and its radicals relatively "take their time reacting", so bromine tends to end up on its preference of carbons. It prefers more substituted carbons: 3° is preferred over 20 is prefered over 10. Given that, which product will be produced in highest yield when bromine undergoes free radical halogenation with 2-methylhexane? O 1-bromo-2-methylhexane 3-bromo-2-methylhexane 5-bromo-6-methylhexane 4-bromo-2-methylhexane 2-bromo-2-methylhexane

QUESTION 25 In this class we will limit our study of free radical halogenation to free radical chlorination and free radical bromination. Bromine is a larger, "slower and fussier" atom than chlorine, and its radicals relatively "take their time reacting", so bromine tends to end up on its preference of carbons. It prefers more substituted carbons: 3° is preferred over 20 is prefered over 10. Given that, which product will be produced in highest yield when bromine undergoes free radical halogenation with 2-methylhexane? O 1-bromo-2-methylhexane 3-bromo-2-methylhexane 5-bromo-6-methylhexane 4-bromo-2-methylhexane 2-bromo-2-methylhexane

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Question 25 In this class, we will limit our study of free radical halogenation to free radical chlorination and free radical bromination. Bromine is a larger, "slower and fussier" atom than chlorine, and its radicals relatively "take their time reacting," so bromine tends to end up on its preference of carbons. It prefers more substituted carbons: 3° is preferred over 2° is preferred over 1°. Given that, which product will be produced in highest yield when bromine undergoes free radical halogenation with 2-methylhexane? Options: - ○ 1-bromo-2-methylhexane - ○ 3-bromo-2-methylhexane - ○ 5-bromo-6-methylhexane - ○ 4-bromo-2-methylhexane - ○ 2-bromo-2-methylhexane
Transcribed Image Text:### Question 25 In this class, we will limit our study of free radical halogenation to free radical chlorination and free radical bromination. Bromine is a larger, "slower and fussier" atom than chlorine, and its radicals relatively "take their time reacting," so bromine tends to end up on its preference of carbons. It prefers more substituted carbons: 3° is preferred over 2° is preferred over 1°. Given that, which product will be produced in highest yield when bromine undergoes free radical halogenation with 2-methylhexane? Options: - ○ 1-bromo-2-methylhexane - ○ 3-bromo-2-methylhexane - ○ 5-bromo-6-methylhexane - ○ 4-bromo-2-methylhexane - ○ 2-bromo-2-methylhexane
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