QUESTION 23At 425°C. Kp-4.18x109 for the following reaction. In one experiment, 0.20atm HBr. O.010atm H2 and 0.010atm Br2 are Introduced into a container.2HBr(g) =H2(g) + Br2(g)The reaction- at equilibrium. Therefore the reaction will

Find out the Q which is not the equilibrium constant If Q > Kp ...........Left side reaction…

QUESTION 23 At 425°C. Kp-4.18x10 for the following reaction. In one experiment, 0.20atm HBr. 0.010atm H2 and 0.010atm Br2 are introduced into a container. 2HBr(g)=H2(g) + Br,(g) The reaction at equilibrium. Therefore the reaction will

QUESTION 23 At 425°C. Kp-4.18x10 for the following reaction. In one experiment, 0.20atm HBr. 0.010atm H2 and 0.010atm Br2 are introduced into a container. 2HBr(g)=H2(g) + Br,(g) The reaction at equilibrium. Therefore the reaction will

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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