QUESTION 23A quality control inspector checks a sample of chips produced by a new machine. A sample of 36 chips was checked and 3 were defective. What isthe 95% confidence interval for the proportion of devetive chips produced by this machine?(0, 0.1736)(-0.0070, 0.1736)(-0.0296, 0.2011)Can't calculate the confidence intervalQUESTION 24In a sample of 25 water specimens taken from a construction site, five contained detectable levels of lead. What is the 99% confidence interval forthe proportion of water specimens that contain detectable levels of lead?(0.0684, 0.3316)(0, 0.4061)(0.0432, 0.3568)Can't calculate the confidence interval QUESTION 26In a survey of 800 parents in UAE, 622 said that moral education has a positive effect on attitude towards others. Find the margin of error (E) for a99% confidence interval for the proportion of parents who believe that moral education has a positive effect. Round your answer to four decimalplaces.QUESTION 27Shamma computed a confidence interval for the mean weight of ZU female students based on a sample of size 40. The weights are not normallydistributed and Shamma used the Student's t distribution for the confidence interval instead of a normal distribution. Her interval is ............ oneobtained by using an appropriate normal distribution.shorter thansame aslarger thanNo enough information

given data,n=36x= no. of defective =3p^=xn=336=0.0833CI=0.95α=1-0.95=0.05we have to find out the…

Answered: QUESTION 23 A quality control inspector…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Could someone help me figure out how to do this problem on a TI 84? Determine the lower bound on the 95% confidence interval with x=2.09, s=0.76, n=1124, rounding to three decimal places.
Suppose we are able to use a normal model. In order to construct a 99% Confidence Interval, we have to find the margin of error (ME), and we can use the following formula: 2.579*SE, where SE is computed with the image that's attached to this problem. Using SE = 0.049, find ME for the 99% Confidence Interval. Round your answer to 3 decimal places.
A random sample of size 49 from normal population yields, mean = 7.2 and standard deviation = 2.8. The lower bound of a 99 percent confidence interval for population mean is O a. 6.40 O b. 6.53 O c. 6.13 O d. 6.68
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