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Question 22 Find the chip capacity for an EPROM with 13 address lines and 8 data lines. Selected Answer: 8192

Question 22 Find the chip capacity for an EPROM with 13 address lines and 8 data lines. Selected Answer: 8192

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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**Question 22** Find the chip capacity for an EPROM with 13 address lines and 8 data lines. **Selected Answer:** 8192 --- ### Explanation: When determining the chip capacity, an EPROM's (Erasable Programmable Read-Only Memory) capacity is calculated by multiplying the number of addressable locations by the data width (number of data lines). - **Address Lines:** 13 address lines mean 2^13 possible addresses. This is because each line can be either 0 or 1, providing a binary combination for addressing. - **Data Lines:** Each address line can contain 8 bits of data (since there are 8 data lines). To find the total capacity in bits: \[ \text{Total Capacity} = 2^{13} \times 8 \] \[ \text{Total Capacity} = 8192 \times 8 = 65536 \text{ bits} \] Therefore, the chip capacity is 65,536 bits or 8,192 bytes (1 byte = 8 bits).
Transcribed Image Text:**Question 22** Find the chip capacity for an EPROM with 13 address lines and 8 data lines. **Selected Answer:** 8192 --- ### Explanation: When determining the chip capacity, an EPROM's (Erasable Programmable Read-Only Memory) capacity is calculated by multiplying the number of addressable locations by the data width (number of data lines). - **Address Lines:** 13 address lines mean 2^13 possible addresses. This is because each line can be either 0 or 1, providing a binary combination for addressing. - **Data Lines:** Each address line can contain 8 bits of data (since there are 8 data lines). To find the total capacity in bits: \[ \text{Total Capacity} = 2^{13} \times 8 \] \[ \text{Total Capacity} = 8192 \times 8 = 65536 \text{ bits} \] Therefore, the chip capacity is 65,536 bits or 8,192 bytes (1 byte = 8 bits).
**Question 10** When Select = 0, Dout will read ______. [Diagram Description] The diagram illustrates a simple circuit with a transistor. It has the following components: - A horizontal line labeled "Select" on the left that connects to the base of the transistor. - A transistor is depicted with an arrow pointing towards the emitter, indicating an NPN type. - The collector of the transistor is connected to a horizontal line on the top labeled "Dout". - The emitter of the transistor is connected to a resistor that is grounded. **Selected Answer**: 1
Transcribed Image Text:**Question 10** When Select = 0, Dout will read ______. [Diagram Description] The diagram illustrates a simple circuit with a transistor. It has the following components: - A horizontal line labeled "Select" on the left that connects to the base of the transistor. - A transistor is depicted with an arrow pointing towards the emitter, indicating an NPN type. - The collector of the transistor is connected to a horizontal line on the top labeled "Dout". - The emitter of the transistor is connected to a resistor that is grounded. **Selected Answer**: 1
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Number of address lines, N=13

Number of data lines, M=8

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