Question 22 An overhanging beam is subjected to a partial uniform load w- 48 kN/m and two point loads P1 297 kN, P2 -319 kN. The beam has a hinge support at point A, a horizontal roller support at point B and a 6 m right overhang as shown below. P1 P2 w (kN/m). 12 m 8 m 3m 3m What is the absolute maximum bending moment in kN-m anywhere on the beam? NOTE: ONLY ENTER ABSOLUTE VALUES. Eor.examole. if you calculate a max positive moment 200 and a max negative moment-205 kN-m, you would enter 205 if you calculate a max positive moment 300 and a max negative moment 292 kN-m, you would enter 300

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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D Question 22
An overhanging beam is subjected to a partial uniform load w 48 kN/m and two point loads P1 297 kN, P2 -319 kN. The beam
has a hinge support at point A, a horizontal roller support at point B and a 6 m right overhang as shown below.
P1
P2
w (kN/m)
12 m
8 m
3 m
What is the absolute maximum bending moment in kN-m anywhere on the beam? NOTE: ONLY ENTER ABSOLUTE VALUES.
Eor.example.
if you calculate a max positive moment = 200 and a max negative moment - -205 kN-m, you would enter 205
if you calculate a max positive moment 300 and a max negative moment 292 kN-m, you would enter 300
Transcribed Image Text:D Question 22 An overhanging beam is subjected to a partial uniform load w 48 kN/m and two point loads P1 297 kN, P2 -319 kN. The beam has a hinge support at point A, a horizontal roller support at point B and a 6 m right overhang as shown below. P1 P2 w (kN/m) 12 m 8 m 3 m What is the absolute maximum bending moment in kN-m anywhere on the beam? NOTE: ONLY ENTER ABSOLUTE VALUES. Eor.example. if you calculate a max positive moment = 200 and a max negative moment - -205 kN-m, you would enter 205 if you calculate a max positive moment 300 and a max negative moment 292 kN-m, you would enter 300
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