Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 20: Balancing Chemical Equations**
---
**Question:**
In the following reaction, what is the correct coefficient for aluminum chloride (AlCl₃)?
\[ \_\_\_\_ \text{Al} + \_\_\_\_ \text{Cl}_2 \rightarrow \_\_\_\_ \text{AlCl}_3 \]
a) **1**
b) **2**
c) **3**
d) **4**
---
To balance this chemical equation, we need to ensure the number of atoms for each element is the same on both the reactant and product sides of the equation.
The initial unbalanced equation is:
\[ \text{Al} + \text{Cl}_2 \rightarrow \text{AlCl}_3 \]
To balance the number of aluminum (Al) atoms, place a coefficient of **2** in front of AlCl₃ on the right side:
\[ \text{Al} + \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Now, there are 2 aluminum atoms on the right, so place a coefficient of **2** in front of Al on the left:
\[ 2 \text{Al} + \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Next, balance the chlorine (Cl) atoms. There are now 6 chlorine atoms on the right (2 AlCl₃ contains 2 × 3 = 6 Cl atoms). Therefore, place a coefficient of **3** in front of Cl₂ on the left:
\[ 2 \text{Al} + 3 \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
The coefficients are now balanced, and the balanced equation is:
\[ 2 \text{Al} + 3 \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Therefore, the correct coefficient for aluminum chloride (AlCl₃) is **2**, corresponding to option b) **2**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8c1eccff-4d99-45a2-a9f3-7cdc9dec6dc3%2F10f0c7d7-c468-4668-9600-68cf084d3384%2F8dgauiu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 20: Balancing Chemical Equations**
---
**Question:**
In the following reaction, what is the correct coefficient for aluminum chloride (AlCl₃)?
\[ \_\_\_\_ \text{Al} + \_\_\_\_ \text{Cl}_2 \rightarrow \_\_\_\_ \text{AlCl}_3 \]
a) **1**
b) **2**
c) **3**
d) **4**
---
To balance this chemical equation, we need to ensure the number of atoms for each element is the same on both the reactant and product sides of the equation.
The initial unbalanced equation is:
\[ \text{Al} + \text{Cl}_2 \rightarrow \text{AlCl}_3 \]
To balance the number of aluminum (Al) atoms, place a coefficient of **2** in front of AlCl₃ on the right side:
\[ \text{Al} + \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Now, there are 2 aluminum atoms on the right, so place a coefficient of **2** in front of Al on the left:
\[ 2 \text{Al} + \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Next, balance the chlorine (Cl) atoms. There are now 6 chlorine atoms on the right (2 AlCl₃ contains 2 × 3 = 6 Cl atoms). Therefore, place a coefficient of **3** in front of Cl₂ on the left:
\[ 2 \text{Al} + 3 \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
The coefficients are now balanced, and the balanced equation is:
\[ 2 \text{Al} + 3 \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Therefore, the correct coefficient for aluminum chloride (AlCl₃) is **2**, corresponding to option b) **2**.
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