Chemistry for Engineering Students
3rd Edition
ISBN:9781285199023
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter1: Introduction To Chemistry
Section: Chapter Questions
Problem 1.6PAE: Use the web to determine the differences in the amounts of aluminum recycled in states where there...
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![**Question 20: Balancing Chemical Equations**
---
**Question:**
In the following reaction, what is the correct coefficient for aluminum chloride (AlCl₃)?
\[ \_\_\_\_ \text{Al} + \_\_\_\_ \text{Cl}_2 \rightarrow \_\_\_\_ \text{AlCl}_3 \]
a) **1**
b) **2**
c) **3**
d) **4**
---
To balance this chemical equation, we need to ensure the number of atoms for each element is the same on both the reactant and product sides of the equation.
The initial unbalanced equation is:
\[ \text{Al} + \text{Cl}_2 \rightarrow \text{AlCl}_3 \]
To balance the number of aluminum (Al) atoms, place a coefficient of **2** in front of AlCl₃ on the right side:
\[ \text{Al} + \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Now, there are 2 aluminum atoms on the right, so place a coefficient of **2** in front of Al on the left:
\[ 2 \text{Al} + \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Next, balance the chlorine (Cl) atoms. There are now 6 chlorine atoms on the right (2 AlCl₃ contains 2 × 3 = 6 Cl atoms). Therefore, place a coefficient of **3** in front of Cl₂ on the left:
\[ 2 \text{Al} + 3 \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
The coefficients are now balanced, and the balanced equation is:
\[ 2 \text{Al} + 3 \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Therefore, the correct coefficient for aluminum chloride (AlCl₃) is **2**, corresponding to option b) **2**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8c1eccff-4d99-45a2-a9f3-7cdc9dec6dc3%2F10f0c7d7-c468-4668-9600-68cf084d3384%2F8dgauiu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 20: Balancing Chemical Equations**
---
**Question:**
In the following reaction, what is the correct coefficient for aluminum chloride (AlCl₃)?
\[ \_\_\_\_ \text{Al} + \_\_\_\_ \text{Cl}_2 \rightarrow \_\_\_\_ \text{AlCl}_3 \]
a) **1**
b) **2**
c) **3**
d) **4**
---
To balance this chemical equation, we need to ensure the number of atoms for each element is the same on both the reactant and product sides of the equation.
The initial unbalanced equation is:
\[ \text{Al} + \text{Cl}_2 \rightarrow \text{AlCl}_3 \]
To balance the number of aluminum (Al) atoms, place a coefficient of **2** in front of AlCl₃ on the right side:
\[ \text{Al} + \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Now, there are 2 aluminum atoms on the right, so place a coefficient of **2** in front of Al on the left:
\[ 2 \text{Al} + \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Next, balance the chlorine (Cl) atoms. There are now 6 chlorine atoms on the right (2 AlCl₃ contains 2 × 3 = 6 Cl atoms). Therefore, place a coefficient of **3** in front of Cl₂ on the left:
\[ 2 \text{Al} + 3 \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
The coefficients are now balanced, and the balanced equation is:
\[ 2 \text{Al} + 3 \text{Cl}_2 \rightarrow 2 \text{AlCl}_3 \]
Therefore, the correct coefficient for aluminum chloride (AlCl₃) is **2**, corresponding to option b) **2**.
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