Question 2. Determine the reactions in supports B and C and the forces in all the members of the planar truss shown in the figure. P-4 kN, BD-DC-a-6 m, |AB|-|CE|-b-8 m. ABLBD, BD1DC, DCLCE 2P B 4P P a D a 6
Question 2. Determine the reactions in supports B and C and the forces in all the members of the planar truss shown in the figure. P-4 kN, BD-DC-a-6 m, |AB|-|CE|-b-8 m. ABLBD, BD1DC, DCLCE 2P B 4P P a D a 6
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![### Structural Mechanics Truss Problem
#### Question 2:
Determine the reactions in supports B and C and the forces in all the members of the planar truss shown in the figure. Given data:
- Load \( P = 4 \) kN
- Length \( |BD| = |DC| = a = 6 \) m
- Length \( |AB| = |CE| = b = 8 \) m
#### Truss Details:
The truss consists of the following segments:
- AB
- BD
- DC
- CE
#### Truss Diagram Description:
The truss diagram is a quadrilateral shape with joints labeled A, B, C, D, and E. The following points describe the layout and loads:
- Joint A is connected to joint B and joint D. There is a horizontal force \( 2P \) acting to the right at joint A.
- Joint B is connected to joint A and joint C. Joint B is positioned vertically below joint A connecting through segment AB.
- Joint C is connected to joint B, joint E, and joint D. A force \( a \) (which is the length |BD| and |DC|) is seen denoting members BD and DC from joint B to C.
- Joint D is connected to joint A, joint B, and joint C. Segment D is defined vertically with \( a \).
- Joint E is at the rightmost bottom corner of the truss with a horizontal load \( 4P \) pointing to the left.
- There is a vertical force \( P \) acting downwards at joint D.
By solving the equilibrium equations for the truss, one should determine the reactions at supports B and C, as well as the forces in all the truss members (AB, BD, DC, CE).
#### Equations:
To determine the reactions and forces, apply the following equilibrium conditions for truss analysis:
1. Sum of Forces in \( x \)-direction (\(\sum F_x = 0\)).
2. Sum of Forces in \( y \)-direction (\(\sum F_y = 0\)).
3. Sum of Moments about any point (\(\sum M = 0\)).
This forms a system of linear equations that can be solved to find the required forces and reactions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0758994e-e825-4b4e-aea1-9b514466c8cb%2F0c497e83-7715-48c0-8f7a-a9b4ddb10a15%2Fofbw69_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Structural Mechanics Truss Problem
#### Question 2:
Determine the reactions in supports B and C and the forces in all the members of the planar truss shown in the figure. Given data:
- Load \( P = 4 \) kN
- Length \( |BD| = |DC| = a = 6 \) m
- Length \( |AB| = |CE| = b = 8 \) m
#### Truss Details:
The truss consists of the following segments:
- AB
- BD
- DC
- CE
#### Truss Diagram Description:
The truss diagram is a quadrilateral shape with joints labeled A, B, C, D, and E. The following points describe the layout and loads:
- Joint A is connected to joint B and joint D. There is a horizontal force \( 2P \) acting to the right at joint A.
- Joint B is connected to joint A and joint C. Joint B is positioned vertically below joint A connecting through segment AB.
- Joint C is connected to joint B, joint E, and joint D. A force \( a \) (which is the length |BD| and |DC|) is seen denoting members BD and DC from joint B to C.
- Joint D is connected to joint A, joint B, and joint C. Segment D is defined vertically with \( a \).
- Joint E is at the rightmost bottom corner of the truss with a horizontal load \( 4P \) pointing to the left.
- There is a vertical force \( P \) acting downwards at joint D.
By solving the equilibrium equations for the truss, one should determine the reactions at supports B and C, as well as the forces in all the truss members (AB, BD, DC, CE).
#### Equations:
To determine the reactions and forces, apply the following equilibrium conditions for truss analysis:
1. Sum of Forces in \( x \)-direction (\(\sum F_x = 0\)).
2. Sum of Forces in \( y \)-direction (\(\sum F_y = 0\)).
3. Sum of Moments about any point (\(\sum M = 0\)).
This forms a system of linear equations that can be solved to find the required forces and reactions.
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