QUESTION 2 The titration between 0.05 M oxalic acid (H₂C₂O4) and 50 ml of 0.1 M potassium hydroxide can be described by the following equation. H₂C2O4 + 2 KOH → K₂C2O4 + 2 H₂O a) Calculate the volume of oxalic acid added at the equivalence point. b) Determine the pH of the solution after 25.0 mL oxalic acid has been added. c) Sketch the complete titration curve for the titration above.

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QUESTION 2
The titration between 0.05 M oxalic acid (H₂C₂O4) and 50 ml of 0.1 M potassium hydroxide
can be described by the following equation.
H₂C2O4 + 2 KOH → K₂C2O4 + 2 H₂O
a) Calculate the volume of oxalic acid added at the equivalence point.
b) Determine the pH of the solution after 25.0 mL oxalic acid has been added.
c) Sketch the complete titration curve for the titration above.
Transcribed Image Text:QUESTION 2 The titration between 0.05 M oxalic acid (H₂C₂O4) and 50 ml of 0.1 M potassium hydroxide can be described by the following equation. H₂C2O4 + 2 KOH → K₂C2O4 + 2 H₂O a) Calculate the volume of oxalic acid added at the equivalence point. b) Determine the pH of the solution after 25.0 mL oxalic acid has been added. c) Sketch the complete titration curve for the titration above.
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