QUESTION 2 The function y = cjex + czeX is a two-parameter family of solutions of the second-order ordinary differential equation y" - y = 0. Find a solution of the second-order Initial-Value Problem (IVP) consisting of this ordinary differential equation and the following initial conditions. y(0) = 2; y'(0) = 2 (type your answers as a numbers in the spaces provided below) y = QUESTION 3 The function y = c,cos(2x) + czsin(2x) is a two-parameter family of solutions of the second-order ordinary differential equation y" + 4y = 0. If possible, find a solution of the second-order ordinary differential equation that satisfies the following boundary conditions (note that conditions specified two different points are called boundary conditions). y(0) = 0; y(7) = 5 (select one of the options presented below) QUESTION 4 Solve the given ordinary differential equation by separation of variables. dy = sin(2x) dx (select one of the options presented below)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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QUESTION 2
The function y = cjex + ceX is a two-parameter family of solutions of the second-order ordinary differential equation y" - y = 0. Find a solution of the second-order Initial-Value Problem (IVP) consisting of this ordinary differential
equation and the following initial conditions.
У (0) — 2; у'(0) — 2
(type your answers as a numbers in the spaces provided below)
y =
eX +
QUESTION 3
The function y = c;cos(2x) + C2sin(2x) is a two-parameter family of solutions of the second-order ordinary differential equation y" + 4y = 0. If possible, find a solution of the second-order ordinary differential equation that
satisfies the following boundary conditions (note that conditions specified at two different points are called boundary conditions).
У (0) — 0; у(л) %— 5
(select one of the options presented below)
QUESTION 4
Solve the given ordinary differential equation by separation of variables.
dy
= sin(2x)
dx
(select one of the options presented below)
Transcribed Image Text:QUESTION 2 The function y = cjex + ceX is a two-parameter family of solutions of the second-order ordinary differential equation y" - y = 0. Find a solution of the second-order Initial-Value Problem (IVP) consisting of this ordinary differential equation and the following initial conditions. У (0) — 2; у'(0) — 2 (type your answers as a numbers in the spaces provided below) y = eX + QUESTION 3 The function y = c;cos(2x) + C2sin(2x) is a two-parameter family of solutions of the second-order ordinary differential equation y" + 4y = 0. If possible, find a solution of the second-order ordinary differential equation that satisfies the following boundary conditions (note that conditions specified at two different points are called boundary conditions). У (0) — 0; у(л) %— 5 (select one of the options presented below) QUESTION 4 Solve the given ordinary differential equation by separation of variables. dy = sin(2x) dx (select one of the options presented below)
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