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Consider the differential equation: y = 3y - 2x Using a pencil, graph the isoclines. Also, using a pen, graph the slope field, as well as three solutions satisfying each of the three conditions: y(0) = 0, y(0) = 1, y(0)=-1.

Consider the differential equation: y = 3y - 2x Using a pencil, graph the isoclines. Also, using a pen, graph the slope field, as well as three solutions satisfying each of the three conditions: y(0) = 0, y(0) = 1, y(0)=-1.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the differential equation: y = 3y - 2x Using a pencil, graph the isoclines. Also, using a pen, graph the slope field, as well as three solutions satisfying each of the three conditions: y(0) = 0, y(0) = 1, y(0)=- 1. 3y-2X=1T => y = (2x +k) 3x y = ²/3 x +ce ³* for y(o) => C=0 => y = /2x for y(o)=1 C= 1 ce // (0) + (2²(0) So, y = 2/x +e³x
Transcribed Image Text:Consider the differential equation: y = 3y - 2x Using a pencil, graph the isoclines. Also, using a pen, graph the slope field, as well as three solutions satisfying each of the three conditions: y(0) = 0, y(0) = 1, y(0)=- 1. 3y-2X=1T => y = (2x +k) 3x y = ²/3 x +ce ³* for y(o) => C=0 => y = /2x for y(o)=1 C= 1 ce // (0) + (2²(0) So, y = 2/x +e³x
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