Question 2 Let W(t) be a standard one dimensional Brownian motion and let Q(t) be the Brownian Bridge on [0, 1], i.e. Q(t) = w(t)tW(1), tɛ [0,1]. 2.1 Show that Q(t) is a Gaussian process with EQ(t)=0, E(Q(t)Q(s)) = min(t, s) — ts. 2.2 Now consider the stochastic process Y(t) = Бакже which is related to the area under the Brownian bridge curve. Show that ts² $3 (ts)2 E (Y(t)Y(s)) = 2 - s

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 78E
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Question 2
Let W(t) be a standard one dimensional Brownian motion and let Q(t) be the Brownian Bridge on [0, 1], i.e.
Q(t) = w(t)tW(1), tɛ [0,1].
2.1 Show that Q(t) is a Gaussian process with
EQ(t)=0, E(Q(t)Q(s)) = min(t, s) — ts.
2.2 Now consider the stochastic process
Y(t) =
Бакже
which is related to the area under the Brownian bridge curve. Show that
ts² $3 (ts)2
E (Y(t)Y(s))
=
2
-
s<t
6
4
2.3 Show that an equivalent definition to Brownian motion is given by
W(t) = (t+1)Q
t
t +1
(Hint: you can use without proof the fact that if X(t) is a Gaussian process then Y(t) = X(f(t)) is Gaussian if
f(t) is a strictly increasing function)
2.4 Show that the solution to the eigenvalue problem
[R(t,s)øk(s)ds = køk(t), R(t, s) = min(t, s) — ts, ¢k(0) = ok (1) = 0
[ok(s) be(s) ds = Skl
(la)
(1b)
is given by
Hence explain why the following holds
1
Ak =
212 ok(t) = √√2 sin kπt
where (k are i.i.d N(0, 1) random variables.
Q(t)=√√sin kat -Sk,
k=1
Επ
(2)
Transcribed Image Text:Question 2 Let W(t) be a standard one dimensional Brownian motion and let Q(t) be the Brownian Bridge on [0, 1], i.e. Q(t) = w(t)tW(1), tɛ [0,1]. 2.1 Show that Q(t) is a Gaussian process with EQ(t)=0, E(Q(t)Q(s)) = min(t, s) — ts. 2.2 Now consider the stochastic process Y(t) = Бакже which is related to the area under the Brownian bridge curve. Show that ts² $3 (ts)2 E (Y(t)Y(s)) = 2 - s<t 6 4 2.3 Show that an equivalent definition to Brownian motion is given by W(t) = (t+1)Q t t +1 (Hint: you can use without proof the fact that if X(t) is a Gaussian process then Y(t) = X(f(t)) is Gaussian if f(t) is a strictly increasing function) 2.4 Show that the solution to the eigenvalue problem [R(t,s)øk(s)ds = køk(t), R(t, s) = min(t, s) — ts, ¢k(0) = ok (1) = 0 [ok(s) be(s) ds = Skl (la) (1b) is given by Hence explain why the following holds 1 Ak = 212 ok(t) = √√2 sin kπt where (k are i.i.d N(0, 1) random variables. Q(t)=√√sin kat -Sk, k=1 Επ (2)
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