question 2  Give the rejection region. Group of answer choices t less than 1.64. z less than 1.64. t greater than 1.64 z greater than 1.64         question 3  Give the test statistic. Group of answer choices z = 1.64 z = -3.25 t = 1.64 t = -3.25

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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question 2 

Give the rejection region.
Group of answer choices
t less than 1.64.
z less than 1.64.
t greater than 1.64
z greater than 1.64
 
 
 
 
question 3 
Give the test statistic.
Group of answer choices
z = 1.64
z = -3.25
t = 1.64
t = -3.25
 
 
question 8
Give the conclusion.
Group of answer choices
Reject the null since the test statistic is in the rejection region.
Fail to reject the null since the test statistic is not in the rejection region.
A new diet is developed to help people lose weight. 50 people tried the
diet and had an average weight loss of 8 pounds over 30 days with a
standard deviation of 2 pounds. A control group of 100 people tried a
standard diet of fruits and vegetables also had an average weight loss of 9
pounds with a standard deviation of 1.2 pounds. Using a 5% significance
determine if the new diet is better than eating fruits and vegetables. Take
as population 1 the group on the new diet.
Give the hypotheses.
O Null: There is no difference in the average weight loss between the two diets.
Alternative: The average weight loss on the new diet is more than the average
weight loss on the fruit and vegetable diet.
O Null: There is no difference in the average weight loss between the two diets.
Alternative: The average weight loss on the new diet is less than the average
weight loss on the fruit and vegetable diet.
O Null: There is no difference in the average weight loss between the two diets.
Alternative: The average weight loss on the new diet is not equal to the average
weight loss on the fruit and vegetable diet.
Transcribed Image Text:A new diet is developed to help people lose weight. 50 people tried the diet and had an average weight loss of 8 pounds over 30 days with a standard deviation of 2 pounds. A control group of 100 people tried a standard diet of fruits and vegetables also had an average weight loss of 9 pounds with a standard deviation of 1.2 pounds. Using a 5% significance determine if the new diet is better than eating fruits and vegetables. Take as population 1 the group on the new diet. Give the hypotheses. O Null: There is no difference in the average weight loss between the two diets. Alternative: The average weight loss on the new diet is more than the average weight loss on the fruit and vegetable diet. O Null: There is no difference in the average weight loss between the two diets. Alternative: The average weight loss on the new diet is less than the average weight loss on the fruit and vegetable diet. O Null: There is no difference in the average weight loss between the two diets. Alternative: The average weight loss on the new diet is not equal to the average weight loss on the fruit and vegetable diet.
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